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kondor19780726 [428]
3 years ago
7

Amelia and Joey decided to shoot arrows at a simple target with a large outer ring and a smaller bull's-eye. Amelia went first a

nd landed 3 arrows in the outer ring and 3 arrows in the bull's-eye, for a total of 267 points. Joey went second and got 4 arrows in the outer ring and 3 arrows in the bull's-eye, earning a total of 281 points. How many points is each region of the target worth? The outer ring is worth ____ points, and the bull's-eye is worth ____ points.
Mathematics
1 answer:
Alona [7]3 years ago
3 0

Answer:

outer ring worth 14 pts

bull's-eye worth 74.333333 pts

Step-by-step explanation:

let the worth point of landing an arrow on the outer ring be "x" and on bull's eye be "y"

For amelia

3x + 3y = 267

For joey

4x + 3y = 281

<em>s</em><em>u</em><em>b</em><em>t</em><em>r</em><em>a</em><em>c</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>f</em><em>i</em><em>r</em><em>s</em><em>t</em><em> </em><em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>f</em><em>r</em><em>o</em><em>m</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>s</em><em>e</em><em>c</em><em>o</em><em>n</em><em>d</em>

x = 14

3x + 3y = 267

42 + 3y = 267

3y = 223

y = 74.333

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