Question

A kid moving 3.78 m/s jumps on a slip and slide (Uk=0.111). After sliding 5.00 m, what is his velocity? Unit=m/s

Answer 1

Newton's Second law of motion:
F=ma => a = F/m = -Uk*mg/m = -Uk*g = -0.111*9.81 = -1.089 m/s^2 (negative sign is because there will be deceleration).

Laws of motion:
v^2 = u^2 + 2ad , v= Final velocity, u= initial velocity, a = acceleration, d = distance moved.
Therefore,
v= Sqrt (u^2+2at) =Sqrt {3.78^2+(-1.089*2*5)} = 1.844 m/s