Ask question

Ask question

All categories

3 years ago

15

If the size of the charge value is tripled for both of twopoint charges maintained at a constant separation, the mutual forcebet

ween them will be changed by what factor?
a. 9.0
b. 3.0
c. 0.33
d. 1/9
e. 6.0

1 answer:

ch4aika [34]3 years ago

8 0

Answer:

a) 9.0

Explanation:

The force between two point charges, obeys Coulomb's Law, which can be written as follows:

$F =\frac{k*q1*q2}{(r12)^{2} }$

As it can be seen, if the separation between the charges remains the same, the new value of the force will be directly proportional to the product of the charges.

If both charges are tripled, the mutual force between them will be changed in a factor equal to 3.0*3.0 = 9.0

You might be interested in

The mass of one atom would best be measured in this unit:

trapecia [35]

Answer:

mass of one atom is measured in the unit of 1 amu

Explanation:

As we know that the mass of one atom is very small and it is of order of $10^{-27}$

here we know that 1 amu is defined as 1/12 part of mass of 1 atom of C-12 isotope

so here we will have

$1 amu = 1.66 \times 10^{-27} kg$

so here we can say that mass of one atom is measured in the unit of 1 amu

8 0

3 years ago

Francium-223 has a half-life of 22 minutes. A Geiger counter gives a reading of 58 counts per minute (cpm) from a sample of fran

polet [3.4K]

Answer:

29 counts per minute (29 cpm)

Explanation:

The half-life of a radioactive isotope is the time needed for the activity of the sample to halve.The half-life of Francium-223 is exactly 22 minutes: this means that its activity after 22 minutes becomes exactly half of its initial value. Since the initial activity of this sample of francium-223 was 58 cpm, the activity after 22 minutes will be

$A=\frac{58 cpm}{2}=29 cpm$

8 0

3 years ago

This is the smallest unit of matter that cannot be physiologically broken down.

yuradex [85]

An atom is the smallest unit of matter. It can't be broken. It consist of dense nuleus surrounded by negatively charged electrons.

4 0

3 years ago

Engineers and science fiction writers have proposed designing space stations in the shape of a rotating wheel or ring, which wou

Gennadij [26K]

Answer:

a. The station is rotating at $1.496 \frac{rev}{min}$

b. the rotation needed is $2.8502 \frac{rev}{min}$

Explanation:

We know that the centripetal acceleration is

$a_{c}= \omega ^2 r$

where $\omega$ is the rotational speed and r is the radius. As the centripetal acceleration is feel like an centrifugal acceleration in the rotating frame of reference (be careful, as the rotating frame of reference is <u>NOT INERTIAL,</u> the centrifugal force is a fictitious force, the real force is the centripetal).

<h3>a. </h3>

The rotational speed is :

$2.7 \frac{m}{s^2} = \omega ^2 * 110 \ m$

$\omega ^2 = \frac{2.7 \frac{m}{s^2}} {110 \ m}$

$\omega = \sqrt{ 0.02454 \frac{rad^2}{s^2} }$

$\omega = 0.1567 \frac{rad}{s}$

Knowing that there are $2\pi \ rad$ in a revolution and 60 seconds in a minute.

$\omega = 0.1567 \frac{rad}{s} \frac{1 \ rev}{2\pi \ rad} \frac{60 \ s}{1 \ min}$

$\omega = 1.496 \frac{rev}{min}$

<h3>b. </h3>

The rotational speed needed is :

$9.8 \frac{m}{s^2} = \omega ^2 * 110 \ m$

$\omega ^2 = \frac{9.8 \frac{m}{s^2}} {110 \ m}$

$\omega = \sqrt{ 0.08909 \frac{rad^2}{s^2} }$

$\omega = 0.2985 \frac{rad}{s}$

Knowing that there are $2\pi \ rad$ in a revolution and 60 seconds in a minute.

$\omega = 0.2985 \frac{rev}{min} \frac{1 \ rev}{2\pi \ rad} \frac{60 \ s}{1 \ min}$

$\omega = 2.8502 \frac{rev}{min}$

3 0

3 years ago

Read 2 more answers

A major contribution of Johannes Kepler to the development of modern astronomy was:________.

fgiga [73]

Answer:

<h2>The answer is planetary motion</h2>

Explanation:

According to Johannes Kepler, the laws governing planetary motion

states that:

1. The orbit of a planet is an ellipse with the Sun at one of the two foci.

2. A line segment joining a planet and the Sun sweeps out equal areas

during equal intervals of time.

3. The square of a planet's orbital period is proportional to the cube of the semi-major of its orbit.

Johannes Kepler was a German astronomer, mathematician, and astrologer

Born: 27 December 1571, Weil der Stadt, Germany

Died: 15 November 1630

8 0

4 years ago