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3 years ago

Emily’s vacuum cleaner has a power rating of 200 watts. If the vacuum cleaner does 360,000 joules of work,

Physics

1 answer:

gtnhenbr [62]3 years ago

7 0

Divide 360000 by 200 to get 1800 seconds, or half of hour.

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A camera lens focuses on an object 75.0 cm from the lensThe image forms 3.50 cm behind the lens. What is the magnification of th

N76 [4]

Answer:

7/150

Explanation:

The following data were obtained from the question:

Object distance (u) = 75cm

Image distance (v) = 3.5cm

Magnification (M) =..?

Magnification is simply defined as:

Magnification (M) = Image distance (v)/ object distance (u)

M = v /u

With the above formula, we can obtain the magnification of the image as follow:

M = v/u

M = 3.5/75

M = 7/150

Therefore, the magnification of the image is 7/150.

6 0

3 years ago

A car starts from rest and accelerates uniformly over a time of 18 seconds for a distance of 390 m. Determine the acceleration o

Sergeeva-Olga [200]

Answer:

$a=2.4\ m/s^2$

Explanation:

Given that,

The initial speed of a car, u = 0

Time, t = 18 s

Distance, d = 390 m

We need to find the acceleration of the car. Let it is a. Using the second equation of motion to find it.

$d=ut+\dfrac{1}{2}at^2$

$d=\dfrac{1}{2}at^2\\\\a=\dfrac{2d}{t^2}\\\\a=\dfrac{2\times 390}{(18)^2}\\\\a=2.4\ m/s^2$

So, the acceleration of the car is $2.4\ m/s^2$ .

5 0

3 years ago

For years, the tallest tower in the United States was the Phoenix Shot Tower in Baltimore, Maryland. The shot tower was used fro

serious [3.7K]

Answer:

The answer to your question is:

a) t = 3.81 s

b) vf = 37.4 m/s

Explanation:

Data

height = 71.3 m = 234 feet

t = 0 m/s

vf = ?

vo = 0 m/s

Formula

h = vot + 1/2gt²

vf = vo + gt

Process

h = vot + 1/2gt²

71.3 = 0t + 1/2(9.81)t²

2(71.3) = 9,81t²

t² = 2(71.3)/9.81

t² = 14.53

t = 3.81 s

vf = 0 + (9.81)(3.81)

vf = 37.4 m/s

3 0

3 years ago

What is the mass of mars

tiny-mole [99]

the mass of mars is

6.39 × 10^23 kg

3 0

2 years ago

During electrical storms, a bolt of lightning can transfer 10 C of charge in 2.0 µs (the amount of time can vary considerably).

nydimaria [60]

Answer:

Explanation:

charge, q = 10 C

time, t = 2 micro second

Current, i = q / t

i = 10 / (2 x 10^-6) = 5 x 10^6 A

(a)

distance, d = 1 m

the formula for the magnetic field is given by

$B = \frac{\mu_{0}}{4\pi}\frac{2i}{d}$

$B = 10^{-7}\frac{2\times 5\times 10^{6}}{1}$

B = 1 Tesla

Now the distance is d' = 1 km = 1000 m

$B' = \frac{\mu_{0}}{4\pi}\frac{2i}{d}$

$B' = 10^{-7}\frac{2\times 5\times 10^{6}}{1000}$

B' = 0.001 Tesla

(b) The magnetic field of earth is Bo = 3 x 10^-5 tesla

B / Bo = 3.3 x 10^4

B'/Bo = 33.3

4 0

3 years ago