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kykrilka [37]
3 years ago
5

If a stone dropped into a well reaches the water's surface after 3.0 seconds, how far did the stone drop before hitting the wate

r?
Physics
1 answer:
pogonyaev3 years ago
8 0
Let h =  distance (m) to the water surface.

Initial velocity, u  = 0 (because the stone was dropped).
Use the formula
 h = ut + (1/2)gt^2
  where g = 9.8 m/s^2  (acc. due to graity)
              t = time (s)

h = (1/2)*(9.8)*(3^2) = 44.1 m
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2.When they reach the bottom of the fall

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Charge is given by

Q=CV\\\Rightarrow Q=k\epsilon\dfrac{A}{d}V\\\Rightarrow Q=5.4\times 8.85\times 10^{-12}\times \dfrac{6\times 10^{-9}}{1.6\times 10^{-8}}\times 86.2\times 10^{-3}\\\Rightarrow Q=1.54481175\times 10^{-12}\ C

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