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3 years ago

14

List examples of foliated and non-foliated rocks. Explain the difference between the two types of metamorphic rocks.

1 answer:

igomit [66]3 years ago

4 0

Non-foliated metamorphic rocks are rocks that have been changed by heat and pressure into rocks with a non-layered or banded appearance. Some examples of non-foliated metamorphic rocks include quartzite, marble, amphibolite and hornfels.

Non-foliated metamorphic rocks are rocks that have been changed by heat and pressure into rocks with a non-layered or banded appearance. Some examples of non-foliated metamorphic rocks include quartzite, marble, amphibolite and hornfels.

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5. You're examining some of the tiny printing on one of the newer twenty-dollar bills. A 1.5 mm tall letter appears 3 mm tall an

kow [346]

Answer:

80mm or 8cm

Explanation:

According to the lens formula,

1/f = 1/u+1/v

If the object distance u = 4cm = 40mm

Object height = 1.5mm

Image height = 3mm

First, we need to get the image distance (v) using the magnification formula Magnification = image distance/object distance = Image height/object height

v/40=3/1.5

1.5v = 120

v = 120/1.5

v = 80mm

The image distance is 80mm

To get the focal length, we will substitute the image distance and the object distance in the mirror formula to have;

1/f = 1/40+1/-80

Note that the image formed by the lens is an upright image (virtual), therefore the image distance will be negative.

Also the focal length of the converging lens is positive. Our formula will become;

1/f = 1/40-1/80

1/f = 2-1/80

1/f = 1/80

f = 80mm

The focal length of the lens 80mm or 8cm

5 0

4 years ago

Read 2 more answers

2. A small piece of dust is located in between two oppositely charged parallel plates where there exists a uniform electric fiel

Alla [95]

Answer:

a

The total charge is $q = 1.6*10^{-4}C$

b

The change in potential energy is $\Delta U = -4*10^{-2}J$

c

The height is $h= 8.2cm$

Explanation:

From the question we are told that the

The magnitude of electric field is $E = 5000N/C$

The number of proton is $N_p = 1*10^{15}$

The distance between the plates is $d = 5cm = \frac{5}{100} = 0.05m$

The total charge can be mathematically represented as

$q = N_p * e$

Where e is the charge on one proton which has a value of $=1.6*10^{-19}C$

Substituting values

$q = 1 *10^{15} * 1.6*10^{-19} = 1.6 *10^{-4}C$

The change in potential energy is mathematically represented ads

$\Delta U = -(qE)d$

where the negative sign shows that the work done by the electric force is against the electric field

Substituting values

$\Delta U = - 1.6*10^{-4} * 5000 * 0.05$

$= -4*10^{-2}J$

The mass of the bead is given as 0.05kg

The change in potential due to gravity is mathematically given as

$\Delta U = -mgh$

the negative sign is due to the fact that the height is decreasing

And $g =9.8m/s^2$

Making h the subject

$h = \frac{\Delta U}{mg}$

Substituting values

$h = \frac{4*10^{-2}}{0.05 * 9.8}$

$=0.081m = 0.082 *100 = 8.2cm$

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4 years ago

Which of these individuals has a sedentary lifestyle

xz_007 [3.2K]

Answer:

<u>A.</u>

Explanation:

A sedentary lifestyle is someone that does not participate in physical activities. Leslie is not active and plays video games instead.

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svetoff [14.1K]

I think it would'nt move at all but im not postive

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4 years ago

What is the mass for both??

alexandr402 [8]

Answer:

ligma

Explanation:

sugondese

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3 years ago