All categories

8 months ago

2×3.14√(1.0m/(9.8〖ms〗^(-1) )=)

Physics

1 answer:

il63 [147K]8 months ago

8 0

This is the period in a simple harmonic motion which is 2 seconds in this question.

<h3>What is Period ?</h3>

The period of an oscillatory object can be defined as the total time taken by a vibrating body to make one complete revolution about a reference point.

We are given the below question

2×3.14√(1.0m/(9.8〖ms〗^(2) )= T

This question can as well be expressed as

2π√(L/g) which is equal to period T.

In a nut shell, Period T = 2×3.14√(1.0m/9.8)

T = 6.28√0.102

T = 6.28 × 0.32

T = 2.006 s

Therefore, the period T of the oscillation is 2 seconds approximately.

Learn more about Period here: brainly.com/question/12588483

#SPJ1

You might be interested in

You can tell from reading this passage that -

Romashka-Z-Leto [24]

Answer: B or "diamonds are rare,valuable gems".

Explanation:

since the link does not show very much, I don't know if A is correct or not. D is incorrect because that is an opinion. C is incorrect.

4 0

3 years ago

Does one of the planets spin backwards on its axis compared to the rest of the planets

mojhsa [17]

Yes they do because they just have to

4 0

2 years ago

A person travelled in the -x direction at a constant speed of 2.5 m/s. The person's final position is -10.0 m, and the initial p

Nostrana [21]

Answer:

Explanation:

We have given the final position = -10 m on x axis

And the initial position =10 m

So total distance = 10-(-10)=20 m

The speed is given as 2.5 m/sec

We have tof ind the time required by the person to travel

Time is given by $t=\frac{distance}{speed}=\frac{20}{2.5}=8 sec$

So the option (c) is correct option

4 0

3 years ago

Investigate the relationship between volume and pressure of a gas at a constant temperature.

sveta [45]

Gay Lussac's Law states: At a constant volume Pressure divided by Temperature isconstant P/T = k Together these three laws form the foundation of the Ideal GasLaw. Objective: Students will investigate Gay Lussac's Law relating pressure andtemperature at a constant temperature.

7 0

3 years ago

When the driver presses the brake pedal, his car stops with an acceleration of - 8.7 m/s. How far will the car travel while comi

klemol [59]

Answer:

D. 5.7 m

Explanation:

The acceleration of the car is -8.7 m/s² and the car has an initial speed (u) of 10 m/s. The car said to come to rest, that means that the final velocity (v) of the car is 0 m/s.

To find the distance traveled by the car (s) before complete stop, this equation is being used:

v² = u² + 2as

$2as=v^2-u^2\\s=\frac{v^2-u^2}{2a}\\ Substituting:\\s=\frac{0-10^2}{2*-8.7}\\ s=\frac{-100}{17.4}\\ s=5.7\ m$

The car traveled 5.7 m before coming to a complete stop

3 0

3 years ago