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Mathematics

1 answer:

raketka [301]3 years ago

8 0

Answer:

(D)Equilateral Triangle

Step-by-step explanation:

Given a circle centre M; and

The measure of major arc JL = 300 degrees

The triangle formed by radii ML and MJ and chord JL is Triangle JLM.

Since ML=MJ (radii of a circle), the base angles are equal.

Therefore:

$\angle MLJ= \angle MJL\\\angle LMJ =60^\circ\\$Therefore:\\\angle LMJ+2\angle MLJ=180^\circ\\60^\circ+2\angle MLJ=180^\circ\\2\angle MLJ=180^\circ-60^\circ\\2\angle MLJ=120^\circ\\\angle MLJ=60^\circ$

We can see that all the angles of triangle JLM are 60 degrees, therefore Triangle JLM is an Equilateral Triangle.

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$\begin{center}
\begin{tabular}
{|p {2cm}|p {2cm}|p {2cm}|p {2cm}|}
\multicolumn {4} {|c|} {Distance Across Quarry Canyon}\\[1ex]
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