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MatroZZZ [7]
3 years ago
14

QHome Spring 2020

Mathematics
1 answer:
raketka [301]3 years ago
8 0

Answer:

(D)Equilateral Triangle

Step-by-step explanation:

Given a circle centre M; and

The measure of major arc JL = 300 degrees

The triangle formed by radii ML and MJ and chord JL is Triangle JLM.

Since ML=MJ (radii of a circle), the base angles are equal.

Therefore:

\angle MLJ= \angle MJL\\\angle LMJ =60^\circ\\$Therefore:\\\angle LMJ+2\angle MLJ=180^\circ\\60^\circ+2\angle MLJ=180^\circ\\2\angle MLJ=180^\circ-60^\circ\\2\angle MLJ=120^\circ\\\angle MLJ=60^\circ

We can see that all the angles of triangle JLM are 60 degrees, therefore Triangle JLM is an Equilateral Triangle.

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Answer:

(x - 5)^2 + y^2 = 225/4,

or you could write it as (x - 5)^2 + y^2 = 56.25.

Step-by-step explanation:

The factor form is

(x - h)^2 + (y - k)^2 = r^2  where the center is (h, k) and r = the radius.

So we have:

(x - 5)^2 + (y - 0)^2 = r^2

As the point  (-1, 9/2) is on the line:

(-1 - 5)^2 +  (9/2)^2 = r^2

r^2 =  36 +  81/4

r^2 = 225/4.

So  substituting for r^2:

(x - 5)^2 + (y - 0)^2 = 225/4

(x - 5)^2 + y^2 = 225/4 is the standard form.

3 0
3 years ago
Solve the equation for m:<br><br> m/5 = 60
alex41 [277]

Answer:

m = 300

Step-by-step explanation:

m/5 = 60

multiply both sides of the equation by 5

m = 60 * 5 = 300

3 0
3 years ago
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Answer:

this might help better

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Mrac [35]
For this case we can model the problem as a rectangle triangle.
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