Definitely not D i would guess A or B
Answer:
18.066 × 10²³ particles
Explanation:
Given data:
Number of moles = 3 moles
Number of particles = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen
For 3 moles of substance:
One mole = 6.022 × 10²³ particles
3 mol × 6.022 × 10²³ particles/ 1 mol = 18.066 × 10²³ particles
Answer:
Explanation:
These properties are governed by intermolecular forces. The most important part here is the oxygen interaction with the surroundings. For temperature the decreasing order is pentanol, pentanal and pentane. For viscocity: pentanol, pentanal and pentane. For surface tension: pentanol, pentanal and pentane.
This order, as said before, is due to the interaction of oxygen with the surroundings, within the intermolecular forces we can find van der waals forces and hydrogen bonds, it is also know that H-bonds are stronger than van der waals forces so then that is why we have this type of interactions.
Answer:
what
Explanation:
Which statement correctly describes how the parts of a flowering plant contribute to its survival? A. Roots prepare the plant for seed production, while the stem releases pollen for fertilization. B. Sepals prepare the plant for pollination, while the leaves collect oxygen for photosynthesis. C. Petals are involved in the reproductive cycle, while stamens protect the plant from predators. D. Ovaries are involved in fertilization and seed production, while anthers and
Answer:
a) 0.100 M
b) 0.395 M
Explanation:
a) Calculate the molarity of a solution that contains 0.200 moles of NaOH (solute) in 2.00 L of solution
We will use the following expression for molarity.
[NaOH] = moles of solute / liters of solution
[NaOH] = 0.200 mol/2.00 L = 0.100 M
b) Calculate the molarity for a solution that contains 15.5 g of NaCl (solute, 58.44 g/mol) in 671 mL of solution
We will use the following expression for molarity.
[NaCl] = mass of solute / molar mass of solute × liters of solution
[NaCl] = 15.5 g / 58.44 g/mol × 0.671 L = 0.395 M
