All categories

3 years ago

Explain how a mummy decreases in mass from 200 to 170 kg

1 answer:

5 0

While the laws of thermodynamics state that matter cannot be created or destroyed, in the mummification process, bodies are capable of losing mass through several ways. One way is in the beginnings of the mummification process itself, where internal organs were removed. While the total weight of internal organs varies, it's generally around 20 pounds, or 9.07 kilograms. Another way the body loses mass in mummification is through the dehydration of bodily tissue through the application of salt to the mummy, both internally and externally. Humans average around 60% of their total body weight being composed of water. Through completely effective, which is nearly impossible, total dehydration of the body would leave only around 40% of the body's initial mass present, (0.4(remaining mass))(200kg)=80 kg, but that is nearly impossible without highly sophisticated instruments with exceptional climate control. However, this dehydration would also decrease a mummy's mass greatly.

You might be interested in

What element has 80 protons, 81 neutrons, 79 electrons?

Mariana [72]

Answer:

The element will be $^{161}_{80}X$

Explanation:

Given that,

Number of proton = 80

Number of neutron = 81

Number of electron = 79

We know that,

The atomic number is equal to the number of proton.

So, the atomic number is 80.

According to atomic number,

The element will be mercury.

We need to calculate the atomic mass

Using formula of atomic mass

$atomic\ mass=atomic\ number+number\ of\ neutron$

Put the value into the formula

$atomic\ mass=80+81$

$atomic\ mass=161$

We need to find the element

Using atomic mass and atomic number

$atomic\ mass\ number A=161$

$atomic\ number Z=80$

So, the element will be

$^{A}_{Z}X$

Put the value of A and Z

Hence, The element will be $^{161}_{80}X$

5 0

3 years ago

What type of circuit is shown in the diagram below?

Rzqust [24]

Answer:

Its a simple SERIES circuit

Explanation:

3 0

3 years ago

Why do the planets in our solar system stay in a system of organized motion?

xeze [42]

Answer:

Explanation:

7 0

3 years ago

A sample of an ideal gas in a cylinder of volume 2.67 L at 298 K and 2.81 atm expands to 8.34 L by two different pathways. Path

Igoryamba

Explanation:

For path A, the calculation will be as follows.

As, for reversible isothermal expansion the formula is as follows.

W = $-2.303 nRT log(\frac{V_2}{V_1})$

Since, we are not given the number of moles here. Therefore, we assume the number of moles, n = 1 mol.

As the given data is as follows.

R = 8.314 J/(K mol), T = 298 K ,

$V_{2}$ = 8.34 L, $V_{1}$ = 2.67 L

Now, putting the given values into the above formula as follows.

W = $-2.303 nRT log(\frac{V_2}{V_1})$

= $-2.303 \times 1 \times 8.314 J/K mol \times 298 log(\frac{8.34}{2.67})$

= $-2.303 \times 1 \times 8.314 J/K mol \times 298 \times 0.494$

= -2818.68 J

Hence, work for path A is -2818.68 J.

For path B, the calculation will be as follows.

Step 1: When there is no change in volume then W = 0

Hence, for step 1, W = 0

Step 2: As, the gas is allowed to expand against constant external pressure $P_{external}$ = 1.00 atm.

So, W = $-P_{external} \times \Delta V$

Now, putting the given values into the above formula as follows.

W = $-P_{external} \times \Delta V$

= $-1 atm \times (8.34 L - 2.67 L)$

= -5.67 atm L

As we known that, 1 atm L = 101.33 J

Hence, work will be calculated as follows.

W = $-\frac{101.33 J}{1 atm L} \times 5.67 atm L$

= -574.54 J

Therefore, total work done by path B = 0 + (-574.54 J)

W = -574.54 J

Hence, work for path B is -574.54 J.

3 0

3 years ago

Some compounds are better known by their common names than by their systematic chemical names. Give the chemical formulas of the

kondaur [170]

Explanation:

(a) Dry ice is solid carbon dioxide and its chemical formula is solid $CO_{2}$ .

(b) Sodium chloride is commonly known as salt in daily life. Hence, chemical formula of salt is NaCl.

(c) Laughing gas is also known as dinitrogen monoxide. Hence, its chemical formula is $N_{2}O$ .

(d) Marble (chalk limestone) is chemically known as calcium carbonate. Hence, its chemical formula is $CaCO_{3}$ .

(e) Baking soda is chemically known as sodium bicarbonate. Hence, its chemical formula is $NaHCO_{3}$ .

(f) Ammonia has a chemical formula as $NH_{3}$ .

(g) Water has a chemical formula as $H_{2}O$ .

(h) Milk of magnesia is a base and it is chemically known as magnesium hydroxide. Its chemical formula is $Mg(OH)_{2}$ .

(i) Epsom salt is most often found as heptahydrate of sulfate mineral epsomite. Its chemical formula is usually $MgSO_{4}.7H_{2}O$ . If not present as a heptahydrate then its chemical formula is $MgSO_{4}.(H_{2}O)_{x}$ where, value of x can be equal to 0 to 7.

5 0

3 years ago