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s2008m [1.1K]
3 years ago
8

Explain how a mummy decreases in mass from 200 to 170 kg

Chemistry
1 answer:
kiruha [24]3 years ago
5 0
While the laws of thermodynamics state that matter cannot be created or destroyed, in the mummification process, bodies are capable of losing mass through several ways. One way is in the beginnings of the mummification process itself, where internal organs were removed. While the total weight of internal organs varies, it's generally around 20 pounds, or 9.07 kilograms. Another way the body loses mass in mummification is through the dehydration of bodily tissue through the application of salt to the mummy, both internally and externally. Humans average around 60% of their total body weight being composed of water. Through completely effective, which is nearly impossible, total dehydration of the body would leave only around 40% of the body's initial mass present, (0.4(remaining mass))(200kg)=80 kg, but that is nearly impossible without highly sophisticated instruments with exceptional climate control. However, this dehydration would also decrease a mummy's mass greatly. 
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4 years ago
which of the following compounds would be considered an electrolyte? a. c6h12o6 b. naoh c. co2 d. agcl
AlekseyPX

Answer: B: NaOH

Explanation:

5 0
1 year ago
At a particular temperature, K 3.39 for the reaction SO2(9) + NO2(9) SOs(9) +NO(9) If all four gases had initial concentrations
Korvikt [17]

Answer:

The equilibrium concentrations are:

[SO2]=[NO2] =  0.563 M

[SO3]=[NO] =  1.04 M

Explanation:

<u>Given:</u>

Equilibrium constant K = 3.39

[SO2] = [NO2] = [SO3] = [NO] = 0.800 M

<u>To determine:</u>

The equilibrium concentrations of the above gases

Calculation:

Set-up an ICE table for the given reaction

         SO2(g) + NO2(g)\rightleftharpoons  SO3(g) + NO(g)

I                0.800      0.800                                  0.800       0.800

C                -x               -x                                         +x             +x

E              (0.800-x)   (0.800-x)                             (0.800+x)   (0.800+x)

The equilibrium constant is given as:

Keq = \frac{[SO3][NO]}{[SO2][NO2]}=\frac{(0.800+x)^{2}}{(0.800-x)^{2}}

3.39=\frac{(0.800+x)^{2}}{(0.800-x)^{2}}

x = 0.2368 M

[SO2]=[NO2] = 0.800 -x = 0.800 - 0.2368 = 0.5632 M

[SO3]=[NO] = 0.800 +x = 0.800 + 0.2368 = 1.037 M

4 0
3 years ago
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SVETLANKA909090 [29]
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See the attachment. I have marked them with a cross.


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4 years ago
A substance is composed of only one kind of Adam and can't be separated into simpler substances are converted into it another su
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Answer:

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