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emmainna [20.7K]
3 years ago
7

Which statements about reducing sugars are true? D‑Glucose (an aldose) is a reducing sugar. The oxidation of a reducing sugar fo

rms a carboxylic acid sugar. A disaccharide with its anomeric carbons joined by the glycosidic linkage cannot be a reducing sugar. Reducing sugars contain ketone groups instead of aldehyde groups. A reducing sugar will not react with the Cu2+ in Benedict's reagent.
Chemistry
1 answer:
qaws [65]3 years ago
4 0

Answer:

The true statements are given below.

Explanation:

1 D glucose is a reducing sugar

2 The oxidation of reducing sugar forms a carboxylic acid sugar.

D glucose is a reducing sugar because glucose contain a free hydroxyl group (-OH)in its anomeric carbon.

 The oxidation of reducing sugar result in the conversion of -CHO group in case of aldose sugar and -CH2OH group in case of ketose sugar into carboxylic acid(-COOH).

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The pH of saliva is normally in the range of 6.4 to 7.0. However, when a person is ill, the person's saliva becomes more acidic.
aleksley [76]

Answer:

Concentration of hydrogen ion, [H^+]=5.0118*10^{-6} M

Explanation:

pH is defined as the negative logarithm of hydrogen ion's concentration.

The lower the value of pH, the higher the acidic the solution is.

The formula for pH can be written as:

pH=-log[H^+]

Given,

pH of the saliva of Marco = 5.3

To calculate: Hydrogen ion concentration in the saliva

Thus, applying in the formula as:

pH=-log[H^+]

5.3=-log[H^+]

So,

log[H^+]=-5.3

[H^+]=10^{(-5.3)}

[H^+]=5.0118*10^{-6} M

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Answer:

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3 years ago
63.5 grams of alcohol having a density of 0.818 g/ml are require for a chemical reaction. How many milliliters of alcohol should
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How many electrons does carbon have? <br> a. 3 <br> b. 6 <br> c. 12 <br> d. 24
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<h3>What are polymers?</h3>
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2 years ago
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