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hoa [83]
3 years ago
12

Please Help! 20 Points!

Mathematics
1 answer:
iVinArrow [24]3 years ago
6 0
\text {x - coordinate = }  \bigg( 5\dfrac{1}{2}  +  3\dfrac{3}{4} \bigg) \div 2

\text {x - coordinate = }  \bigg( 5\dfrac{2}{4}  +  3\dfrac{3}{4} \bigg) \div 2

\text {x - coordinate = } 8\dfrac{5}{4}   \div 2

\text {x - coordinate = }\dfrac{37}{4}   \times  \dfrac{1}{2}

\text {x - coordinate = }\dfrac{37}{8}

\text {x - coordinate = } 4\dfrac{5}{8}



\text {y - coordinate = } \bigg( -4\dfrac{1}{4} - 1\dfrac{1}{4} \bigg) \div 2

\text {y - coordinate = } -5\dfrac{2}{4} \div 2

\text {y - coordinate = } -\dfrac{22}{4} \times  \dfrac{1}{2}

\text {y - coordinate = } -\dfrac{11}{4}}

\text {y - coordinate = } -2\dfrac{3}{4}}



\text {The coordinate is }\bigg( 4\dfrac{5}{8}, -2\dfrac{3}{4}} \bigg)

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What expression is equivalent to 8p^3+23
garri49 [273]

Answer:

Step-by-step explanation:

I don't know what your choices were, but

8p^2 + 23 = 8p^3 + 27 - 4

= ((2p)^3 + 3^3) - 4

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3 years ago
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5 0
3 years ago
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Luba_88 [7]

we conclude that for 500 miles, both plans will have the same cost.

<h3>For how many miles both plans have the same cost?</h3>

Plan A charges a fixed amount of $75, plus $0.10 per mile, so if you drive x miles, the cost equation is:

A(x) = $75 + $0.10*x

For plan B we will have the similar equation:

B(x) = $100 + $0.05*x

The cost is the same in both plans when:

A(x) = B(x)

So we need to solve the linear equation:

$75 + $0.10*x =  $100 + $0.05*x

$0.10*x - $0.05*x = $100 - $75

$0.05*x = $25

x = $25/$0.05 = 500

So we conclude that for 500 miles, both plans will have the same cost.

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

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