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IgorLugansk [536]
4 years ago
15

igneous rocks that are dense and dark-colored thet form from magma that is rich in iron and magnesium and poor in silica

Chemistry
2 answers:
nekit [7.7K]4 years ago
4 0

light-colored, silica-rich igneous rock that is less dense than basaltic rock. dense, dark-colored igneous rock formed from magma;rich in magnesium and iron and poor in silica. Describes magma or igneous rock that is rich in feldspars and silica and that is generally light in color.

Olegator [25]4 years ago
3 0
Light colored silica rich ringeous rock than is less than dense than bacsaltical rock
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Some examples of physical properties(something I can test for that doesn’t change what the substance is)are
melisa1 [442]

Answer:

v

Explanation:

7 0
3 years ago
The uncertainty in the measurement 1500 m is
erastova [34]

Answer:

Its 1500 meters, which is equal to 0.9320568 miles. Hope this helps!

Explanation:

8 0
3 years ago
A reaction A(aq)+B(aq)↽−−⇀C(aq) has a standard free‑energy change of −4.20 kJ/mol at 25 °C. What are the concentrations of A, B,
Dafna1 [17]

Answer : The concentration of A,B\text{ and }C at equilibrium are 0.132 M, 0.232 M  and 0.168 M  respectively.

Explanation :

The given chemical reaction is,

A(aq)+B(aq)\rightleftharpoons C(aq)

First we have to calculate the equilibrium constant for the reaction.

The relation between the equilibrium constant and standard free‑energy is:

\Delta G^o=-RT \ln k

where,

\Delta G^o = standard free‑energy change = -4.20 kJ/mole

R = universal gas constant = 8.314 J/mole.K

k = equilibrium constant = ?

T = temperature = 25^oC=273+25=298K

Now put all the given values in the above relation, we get:

-4.20kJ/mole=-(8.314J/mole.K)\times (298K) \ln k

k=5.45

Now we have to calculate the concentrations of A, B, and C at equilibrium.

The given equilibrium reaction is,

                          A(aq)+B(aq)\rightleftharpoons C(aq)

Initially               0.30      0.40         0  

At equilibrium  (0.30-x) (0.40-x)     x

The expression of equilibrium constant will be,

k=\frac{[C]}{[A][B]}

5.45=\frac{x}{(0.30-x)\times (0.40-x)}

By solving the term x, we get

x=0.168\text{ and }0.716

From the values of 'x' we conclude that, x = 0.716 can not more than initial concentration. So, the value of 'x' which is equal to 0.716 is not consider.

The value of x will be, 0.168 M

The concentration of A at equilibrium = (0.30-x) = 0.30 - 0.168 = 0.132 M

The concentration of B at equilibrium = (0.40-x) = 0.40 - 0.168 = 0.232 M

The concentration of C at equilibrium = x = 0.168 M

3 0
4 years ago
The partial pressures of the gases in a mixture are 0.255 atm 0, 3.24 atm Ny,
katovenus [111]
<h3>Answer:</h3>

4.945 atm

<h3>Explanation:</h3>
  • Based on Dalton's law of Partial pressure, the total pressure of a mixture of gases is equivalent to the sum of individual partial pressures of the gases in the mixture.
  • That is;

Pt = P1+P2+P3+P4+............+ Pn

In this case;

Partial pressure of Oxygen, P(O) = 0.255 atm

Partial pressure of N, P(N) = 3.24 atm

Partial pressure of Ar, P(Ar) = 1.45 atm

Therefore;

P(total) = P(O) + P(N) + P(Ar)

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Therefore, the total pressure of the mixture is 4.945 atm

6 0
4 years ago
A substance has a high melting point and conducts electricity in the liquid phase The is substance is
posledela

Answer:

oxygen

Explanation:

?

3 0
4 years ago
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