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IgorLugansk [536]

3 years ago

15

igneous rocks that are dense and dark-colored thet form from magma that is rich in iron and magnesium and poor in silica

2 answers:

nekit [7.7K]3 years ago

4 0

light-colored, silica-rich igneous rock that is less dense than basaltic rock. dense, dark-colored igneous rock formed from magma;rich in magnesium and iron and poor in silica. Describes magma or igneous rock that is rich in feldspars and silica and that is generally light in color.

Olegator [25]3 years ago

3 0

Light colored silica rich ringeous rock than is less than dense than bacsaltical rock

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Note that butane has two possible isomers but that decane has 75 possible isomers. Why does the number of possible isomers go up

iren [92.7K]

Because the number of constitutional, conformational, and geometric isomers goes up with each carbon atom added. There are many more possible configurations and connectivities possible with decane, a 10 carbon chain, than with butane, a 4 carbon chain.

7 0

3 years ago

If 525 N of force is applied to a 4.5<br> kg mass, how fast will it accelerate?

wariber [46]

Answer:

121.11m/s²

Explanation:

Given parameters:

Force = 525N

Mass = 4.5kg

Unknown:

Acceleration = ?

Solution:

From Newton's second law of motion, we can find the solution to this problem. Using the expression below:

F = m x a

F is the force

m is the mass

a is the acceleration

So'

525 = 4.5 x acceleration

Acceleration = 121.11m/s²

4 0

3 years ago

In living organisms, C-14 atoms disintegrate at a rate of 15.3 atoms per minute per gram of carbon. A charcoal sample from an ar

Schach [20]

Answer:

The answer is "4,241 .17 years"

Explanation:

The disintegration rate, which shows in C-14 atoms = $15.3 \frac{atoms}{min-g}$

Rate of sample disintegration = $9.16 \frac{atoms} {min-gram}$

The digit proportion of C-14 can be determined that is included in the sample $= \frac {9.16}{15.3} \\\\ = 0.5987$

5730 years from half-life.

The number with half-lives (n) which are repelled must be determined:

$(\frac{1}{2})^n= A\\\\A= fraction of C-14, which is remaining \\\\(\frac{1}{2})^n= 0.5987 \\\\ n \log 2 = - \log 0.5987\\\\$

$\therefore \\\\ \Rightarrow n= \frac{0.227}{0.3010} \\\\ = 0.740\\$

So, the age of the sample is given by = $n \times\ half-life$

$= 0.740 \times 5730 \ years \\\\=4241.17 \ years\\\\$

6 0

3 years ago

A type of covalent bond in which electrons are shared equally between atoms, resulting in no positive or negative side of the mo

Marianna [84]

It’s called a non-polar covalent bond.

7 0

3 years ago

What information do the chemical hazard label and msds have in common

snow_tiger [21]

They tell you to have caution.

6 0

3 years ago