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Elodia [21]
2 years ago
15

Calculate the volume of 12.0 g of helium at 100°c and 1.2 atm

Chemistry
1 answer:
hodyreva [135]2 years ago
8 0

Volume = nRT/P

n = number of particles (moles)

R = universal gas constant (0.0821)

T = temperature (Kelvin)

P = pressure (atm)

(Assuming you have 1 mole of Helium in a chemical reaction) We would need to convert grams to moles: 12.0g He x 1 mol He/4 molar mass of He = 3 mol He

Convert Celsius to Kelvin: 100*C + 273.15 = 373.15 K

Now we can set up the equation for volume: (3mol)(0.0821)(373.15)/1.2atm = 76.6 L of Helium gas

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In an acid/base lab, a student used blue litmus paper and placed it in the sample. It stayed blue. Then the student used red lit
Allushta [10]

Answer: The substance is neutral

Explanation:

If you place red litmus paper into a basic substance, it turn's blue. When it comes in contact with an acidic or neutral substance, it doesn't change colour it remains red.

Blue litmus paper in acid turns red when placed in a basic or neutral solution it remains blue. From this it can be concluded that the solution is neutral.

7 0
3 years ago
1. How many milliliters of 10.0 M HNO 3 are needed to prepare 0.350 L of 0.400 M solution?
tatyana61 [14]
<h3>Answer:</h3>

14 milliliters

<h3>Explanation:</h3>

We are given;

  • 10.0 M HNO₃

Prepared solution;

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  • Molarity as 0.40 M

We are required to determine the initial volume of HNO₃

  • We are going to use the dilution formula;
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M₁V₁ = M₂V₂

Rearranging the formula;

V₁ = M₂V₂ ÷ M₁

    =(0.40 M × 0.350 L) ÷ 10.0 M

   = 0.014 L

But, 1 L = 1000 mL

Therefore,

Volume = 14 mL

Thus, the volume of 10.0 M HNO₃ is 14 mL

5 0
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3 years ago
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