<u>Answer:</u> The volume of the gas when the pressure and temperature has changed is 0.811 L
<u>Explanation:</u>
To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.
The equation follows:
where,
are the initial pressure, volume and temperature of the gas
are the final pressure, volume and temperature of the gas
We are given:
Conversion factor used:
1 L = 1000 mL
1 atm = 760 mmHg
![P_1=1.00atm=760mmHg\\V_1=790mL=0.790L\\T_1=37^oC=[37+273]K=310K\\P_2=695mmHg\\V_2=?L\\T_2=18^oC=[18+273]K=291K](https://tex.z-dn.net/?f=P_1%3D1.00atm%3D760mmHg%5C%5CV_1%3D790mL%3D0.790L%5C%5CT_1%3D37%5EoC%3D%5B37%2B273%5DK%3D310K%5C%5CP_2%3D695mmHg%5C%5CV_2%3D%3FL%5C%5CT_2%3D18%5EoC%3D%5B18%2B273%5DK%3D291K)
Putting values in above equation, we get:
Hence, the volume of the gas when the pressure and temperature has changed is 0.811 L
Answer:
Reaction Quotient, Kq = {[a-ketoglutarate]x[L-alanine]}/{[L-glutamate]x[pyruvate]}
or, Kq = {(1.6x10-2)x(6.25x10∧-3)}/{(3x10∧-5)x(3.3x10-4)} = 1.01 x 10∧4
Since Kq > Keqb ; therefore the reaction will proceed in the backward direction, in order words the reaction will not occur in forward direction. i.e formation of reactants will be favored.
Explanation:
Answer: it is liquid at most temperatures on earth.
Step-by-step explanation:
