1.979 multiply 1979 by 0.001
Answer:
Bb and Bb
Explanation:
This will give you the desired results of one homogeneous BB (brown), two heterogeneous Bb (brown), and one homogeneous bb (tan).
There are 17.97 moles of calcium chloride would react with 5. 99 moles of aluminum oxide .
The balanced chemical equation between reaction between calcium chloride and aluminum oxide is given as,
→
The molar ratio of above reaction is 3:1
It means 3 moles of calcium chloride is require to react one mole of aluminum oxide.
The number of moles of calcium chloride requires to react with 5. 99 moles of aluminum oxide = 3 × 5. 99 = 17.97 moles
The equation in which number of atoms of elements in reactant side is equal to the number of atoms of elements in product side is called balanced chemical equation .
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Answer:
k = 3.2 x 10¹¹
Explanation:
The equilbrium taking place is:
- N₂(g) + 3Cl₂(g) ↔ 2NCl₃(g)
And the expression for the equilbrium constant <em>k</em> is
- k = [NCl₃]² / ( [N₂] * [Cl₂]³)
We are given all the required data from the problem, so now we <u>solve for k</u>:
- k = (1.9x10⁻¹)² / ( (1.4x10⁻³) * (4.3x10⁻⁴)³ )
Explanation:
The four main categories of mineral formation are: (1) igneous, or magmatic, in which minerals crystallize from a melt, (2) sedimentary, in which minerals are the result of sedimentation, a process whose raw materials are particles from other rocks that have undergone weathering or erosion, (3) metamorphic,