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salantis [7]
4 years ago
9

Anton thinks that glucose is a reactant of photosynthesis, but his classmate Jamila disagrees.

Chemistry
2 answers:
Nataly [62]4 years ago
7 0
The right answer would be 3 

morpeh [17]4 years ago
4 0
3. Jamila is correct because glucose is a product, not a reactant, of photosynthesis.

Water + CO2 --> Glucose + O2
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Observe: Select the ELECTRON CONFIGURATION tab. Make sure the subshells are ordered by Energy, which will arrange them from lowe
Mrrafil [7]

Answer:

The order in which the orbitals is filled is 1s-2s-2p-3s-3p-4s-3d-4p-5s-4d-5p-6s-4f-5d-6p-7s-5f-6d-7p

Explanation:

S orbitals each hold two electrons, p orbitals hold 6, d orbitals hold 10, and f orbitals hold 14. 1s has the least energy and 7 p has the greatest energy, so the order in which they are filled is listed above.

7 0
3 years ago
Why is a homogeneous mixture not considered a pure substance?
stepladder [879]
The answer is "A. a pure substance can be separated by chemical means, while a mixture can be separated by physical means". A pure substance only has one type of substance, whereas a mixture has more than one. A pure substance therefore, can only be separated chemically, because it is not two things mixed together, whereas a mixture can be separated physically because there are multiple substances.
4 0
3 years ago
Please help me...
REY [17]

200 Fahrenheit 200 c  

7 0
4 years ago
The percent yield of this reaction is consistently 92.0%. CH4(g) + 4 S(g) → CS2(g) + 2 H2S(g) How many grams of sulfur would be
dybincka [34]

Answer:

132.17 g

Explanation:

The reaction given , in the question is -

    CH₄ (g ) + 4 S ( g ) ---> CS₂ ( g ) + 2H₂S  ( g )

From the reaction , 4 mole of S is required for the production of 1 mole of  CS₂ .

since ,

Moles of  CS₂  = given mass of CS₂ / Molecular weight  of  CS₂

Since ,

the Molecular weight of  CS₂ = 76

Given ,  mass of CS₂ =  72.57 g

Moles of  CS₂ = 72.57  / 76 = 0.95 mol

Since ,

The yield is 92.0 % .

Moles of S required = 4 * 0.95 mol / 0.92 = 4.13 moles

Mass of S required = 4.13 * 32 = 132.17 g .

6 0
3 years ago
Which substance below is resonance stabilized by delocalized pi electrons?
mariarad [96]
If you do not this, I suggest brushing up on delocalization as well as sigma/pi bonds. Benzene is the only one of the 5 with any pi bonds, so this should be a relatively easy question if you are familiar with the concepts. I would search up a detailed (not to detailed though) explanation of both.
8 0
3 years ago
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