Y = 1 3 -x = left[y \right] = \left[ 3-x\right][y]=[3−x]
Answer:
75
Step-by-step explanation:
f(1) = 7
f(n) = 3f(n-1) + 3
So what you are trying to do here is find the recursive value (that's what it is called) for f(n). Computers love this sort of thing, but we humans have to do it slowly and carefully.
So let's try f(2)
That means that f(2) = 3*f(n-1) + 3
but if f(2) is used it means that you have to know f(2-1) which is just f(1) and we know that.
so f(2) = 3*f(1)+3
f(2) = 3*7 + 3
f(2) = 21 + 3
f(2) = 24
Now do it again. We now know F(2), so we should be able to find f(3)
f(3) = 3*f(3 - 1) + 3
f(3) = 3*f(2) + 3 We know that f(2) = 24
f(3) = 3* 24 + 3
f(3) = 72 + 3
f(3) = 75
Answer:
Solutions are -10 and 26
Step-by-step explanation:
( - the abolute sign I'm using
( x - 8 ) + 2 = 20
( x - 8 ) = 18
x - 8 = 18 (postive case)
x - 8 + 8 = 18 + 8
x = 26
( x - 8 ) = 18
x - 8 = -18 (negative case)
x - 8 + 8 = -18 + 8
x = -10
Answer:
try B for an answer, hope it helps
A linear equation can be represented by:
y = mx + b
Where m = slope, and b = y intercept.
The slope is a rate of change, so our slope is $150.
The y intercept is the point where the equation crosses the y axis, or the "initial amount" in this case $500.
So our equation will be:
y = 150x + 500.
