All categories

4 years ago

What volume in L of a 0.375 M solution of NaOH is needed to provide 15.3 g NaOH?

Chemistry

1 answer:

anyanavicka [17]4 years ago

3 0

Answer:

V= 10.2L

Explanation:

NB , n= m/M= CV

Molar mass of NaOH= 40gmol-1

15.3/40= 0.0375×V

Simplify

V= 10.2L

You might be interested in

How many molecules of Iron(II)oxide are present in 35.2*10^-23 g of Iron (II)oxide?

slava [35]

Answer:

R.F.M of Iron (II) oxide :

${ \tt{ = (56 \times 2) + (16 \times 3)}} \\ = 160 \: g$

Moles :

${ \tt{ \frac{35.2 \times {10}^{ - 23} }{160} }} \\ = 2.2 \times {10}^{ - 24} \: moles$

Molecules :

${ \tt{ = 2.2 \times {10}^{ - 24} \times 6.02 \times {10}^{23} }} \\ = 1.3244 \: molecules$

4 0

3 years ago

Calculate the number of moles in the following: 2.8 X 10^24 atoms of Cl2

vova2212 [387]

Answer:

<h3>The answer is 4.65 moles</h3>

Explanation:

To find the number of moles given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 2.8 × 10²⁴ atoms of Cl2

So we have

$n = \frac{2.8 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 4.65116279069...$

We have the final answer as

<h3>4.65 moles</h3>

Hope this helps you

7 0

3 years ago

How many grams of H3PO4 are in 175mL of a 2.50M solution of H3PO4?

solmaris [256]

<span>(0.1875 moles)(98.004 g/mole) = 18.37575 g </span>
<span>In correct number of significant figures: 18.4 </span>

5 0

3 years ago

Read 2 more answers

What would you get if you could break an element into its smallest particles

attashe74 [19]

If you broke an element down to its smallest particles you would get an atom.

4 0

4 years ago

Narceine is a narcotic in opium that crystallizes from solution as a hydrate that contains 10.8 mass % water and has a molar mas

Leto [7]

Thewater of hydration x in narceine. xH₂O is 3

<h3>What is Water of Hydration?</h3>

In chemistry, water molecules found inside crystals are referred to as "water of crystallization" or "water of hydration." When crystals are formed from aqueous solutions, water is frequently included.
The entire mass of water in a substance at a specific temperature is sometimes referred to as water of hydration, and it is typically present in a stoichiometric ratio.
The term "water of crystallization" has historically been used to describe water that is not physically linked to the metal cation but is present in the crystalline structure of a metal complex or salt.
Many chemicals include water molecules in their crystalline structures when they crystallize from water or solvents that contain water. Heating a sample usually removes the water of crystallization, but the crystalline qualities are frequently lost.

Given that hydrate is 10.8% by mass

molar mass = 499.52 g/mol

calculating the amount of water

mass of water = $\dfrac{10.8 \times 499.5}{100}$