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frozen [14]
3 years ago
10

An unknown metal displaces Ali from solution but does not displace sodium using the activity series determine the unknown metal

Chemistry
1 answer:
MAXImum [283]3 years ago
8 0

Answer:

The reactivity of metal is determined by the reactivity series. ... The metal which easily displaced aluminium will lie above in the series but that same element cannot displace sodium, so it will lie below in the series. Hence, from the series, we conclude that the unknown metal could be calcium or magnesium.

Explanation:

Hope this helps! :)

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if you had to explain to someone the difference between heat and temperature, how could you use one of the following to demonstr
Rainbow [258]

Answer:

We associate paper money or points in video games, as molecules that make a heat transfer or an increasin in its temperature.

Explanation:

The meaning of heat is associated with an energy transfer, where for example if we put a spoon in a cup of hot drink, the drink will be transferring heat to the spoon. It is a transfer of energy between two bodies due to a difference between their temperatures.

Temperature is associated with the movement of kinetic energy of the molecules. When the temperature is higher, the kinetic energy is higher, so as more detained they are, temperature will be lower.

If we take paper money as molecules, the greater movement of money explains that we have an increase in temperature (we would be hot), even if we think of video games, for example gambling where as more points we gain, we generate an increase in the movement of "molecules".

When we use paper money to buy something we are doing a heat transfer.

We can associate terms to the Thermodynamic where

Heat = Internal energy + work

For clearance would be

Internal energy = Heat - Work

The money we use less the work we do keeps our internal energy. If in a gambling video game, we earn points over and over again, when withdrawing the prize we perform "heat transfer".

4 0
3 years ago
If 18.1 mLmL of 0.800 M HClM HCl solution are needed to neutralize 5.00 mLmL of a household ammonia solution, what is the molar
AnnyKZ [126]

Answer:

Concentration of ammonia = 3M

Explanation:

The reaction for the question is a neutralization reaction between HCl and NH₃

The chemical equation for the reaction is given as

HCl + NH₃ → NH₄CL

1       :     1          1

Volume of HCl = 18.1ml = 0.0181L

Volume of NH₃ = 5ml= 0.005L

Molar concentration of HCl=0.8M

Molar Concentration of NH₃ =?

Number of moles(n)= Molar concentration × Volume

n = C × V

n of HCL= 0.8 × 0.0181

n = 0.01448moles

Since mole ration for the reaction from the balanced equation above is 1:1,

n of NH₃ = 0.01448

molar concentration (C) of NH₃ = n/v

C of NH₃ = 0.01448/0.005

C of NH₃=2.896

C OF NH₃ =3M

4 0
3 years ago
Calculate how many grams of sodium azide (NaN3) are needed to inflate a 25.0 × 25.0 × 20.0 cm bag to a pressure of 1.35 atm at a
Luden [163]

Answer : The mass of NaN_3 at temperature 20^oC 28.47 g.

The mass of NaN_3 at temperature 10^oC 29.51 g.

Solution : Given,

Pressure of gas = 1.35 atm

Temperature of gas = 20^oC=273+20=293K     (0^oC=273K)

Volume of gas = 25\times 25\times 20cm=12500cm^3=12.5L   (1L=1000cm^3)

Molar mass of NaN_3 = 65 g/mole

Part 1 : First we have to calculate the moles of gas at temperature 20^oC. The gas produced in the given reaction is N_2.

Using ideal gas equation,

PV=nRT

where,

P = pressure of the gas

V = volume of the gas

T = temperature of the gas

n = number of moles of gas

R = Gas constant = 0.0821 Latm/moleK

Now put all the given values in this formula, we get

(1.35atm)\times (12.5L)=n\times (0.0821Latm/moleK)\times (293K)

By rearranging the terms, we get the value of 'n'

n=0.7015moles

The moles of N_2 = 0.7015 moles

The given balanced reaction is,

20NaN_3(s)+6SiO_2(s)+4KNO_3(s)\rightarrow 32N_2(g)+5Na_4SiO_4(s)+K_4SiO_4(s)

As, 32 moles of N_2 produced from 20 moles of NaN_3

So, 0.7015 moles of N_2 produced from \frac{20}{32}\times 0.7015=0.438 moles of NaN_3

Now we have to calculate the mass of NaN_3.

\text{ Mass of }NaN_3=\text{ Moles of }NaN_3\times \text{ Molar mass of }NaN_3

\text{ Mass of }NaN_3=(0.438moles)\times (65g/mole)=28.47g

Therefore, the mass of NaN_3 needed are 28.47 g.

Part 2 : We have to calculate the moles of gas at temperature 10^oC and same volume & pressure.

Using ideal gas equation,

PV=nRT

Now put all the given values in this formula, we get

(1.35atm)\times (12.5L)=n\times (0.0821Latm/moleK)\times (283K)

By rearranging the terms, we get the value of 'n'

n=0.726moles

The moles of N_2 = 0.726 moles

The given balanced reaction is,

20NaN_3(s)+6SiO_2(s)+4KNO_3(s)\rightarrow 32N_2(g)+5Na_4SiO_4(s)+K_4SiO_4(s)

As, 32 moles of N_2 produced from 20 moles of NaN_3

So, 0.726 moles of N_2 produced from \frac{20}{32}\times 0.726=0.454 moles of NaN_3

Now we have to calculate the mass of NaN_3.

\text{ Mass of }NaN_3=\text{ Moles of }NaN_3\times \text{ Molar mass of }NaN_3

\text{ Mass of }NaN_3=(0.454moles)\times (65g/mole)=29.51g

Therefore, the mass of NaN_3 needed are 29.51 g.

7 0
4 years ago
Water is considered a polar solvent due to attractive forces known as hydrogen bonds. a hydrogen bond is:_________
muminat

Because of the attraction forces known as hydrogen bonding, water is referred to as a polar solvent. An attraction between molecules known as a hydrogen bond occurs when partially positive hydrogen atoms are drawn to partially negative F, O, or N atoms.

<h3>What is a hydrogen bond?</h3>

A hydrogen bond (or H-bond) is a strong electrostatic attraction between an electronegative atom holding a lone pair of electrons, known as the hydrogen bond acceptor, and a hydrogen (H) atom that is covalently attached to a more electronegative "donor" atom or group.

<h3>How can hydrogen atoms join together?</h3>

When a hydrogen atom bonds with an electronegative atom, powerful intermolecular forces called hydrogen bonds are produced. The hydrogen bond acceptor's electronegativity will rise, resulting in a stronger hydrogen bond.

To know more about Hydrogen Bond visit:

brainly.com/question/10904296

#SPJ4

4 0
2 years ago
What is the osmolarity of .00001 grams (0.1 mg%) of ethanol (does not dissociate) in one liter?
MrMuchimi

Explanation:

As it is known that non-electrolytes do not dissociate. Therefore, molarity of such a solution is equal to the osmolarity of solution.

As, molar mass of ethanol = 46.07 g/mol

Therefore, no. of moles of ethanol will be calculated as follows.

               No. of moles = \frac{mass}{\text{molar mass}}

                                     = \frac{0.00001 g}{46.07 g/mol}

                                     = 2.17 \times 10^{-7} mol

As, molarity is moles of solute in liter of solution. Hence, molarity of ethanol is as follows.

                           Molarity = \frac{\text{no. of moles}}{volume}

                                          = \frac{2.17 \times 10^{-7} mol}{1 L}

                                          = 2.17 \times 10^{-7} mol/L

Since, for the given solution Molarity = osmolarity

Thus, we can conclude that osmolarity of .00001 grams (0.1 mg%) of ethanol  in 1 L is 2.17 \times 10^{-7} osmol/L.

8 0
3 years ago
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