Question

How many molecules of Iron(II)oxide are present in 35.2*10^-23 g of Iron (II)oxide?

Answer 1

Answer:

R.F.M of Iron (II) oxide :

${ \tt{ = (56 \times 2) + (16 \times 3)}} \\ = 160 \: g$

Moles :

${ \tt{ \frac{35.2 \times {10}^{ - 23} }{160} }} \\ = 2.2 \times {10}^{ - 24} \: moles$

Molecules :

${ \tt{ = 2.2 \times {10}^{ - 24} \times 6.02 \times {10}^{23} }} \\ = 1.3244 \: molecules$