The energy required to remove an electron from an atom ____ as you move left to right from potassium through iron.

2K + 2HBr → 2 KBr + H2

Inessa [10]

Answer:

$\large \boxed{\text{0.0503 g}}$

Explanation:

The limiting reactant is the reactant that gives the smaller amount of product.

Assemble all the data in one place, with molar masses above the formulas and masses below them.

M_r: 39.10 80.41 2.016

2K + 2HBr ⟶ 2KBr + H₂

m/g: 5.5 4.04

a) Limiting reactant

(i) Calculate the moles of each reactant

$\text{Moles of K} = \text{5.5 g} \times \dfrac{\text{1 mol}}{\text{31.10 g}} = \text{0.141 mol K}\\\\\text{Moles of HBr} = \text{4.04 g} \times \dfrac{\text{1 mol}}{\text{80.91 g}} = \text{0.049 93 mol HBr}$

(ii) Calculate the moles of H₂ we can obtain from each reactant.

From K:

The molar ratio of H₂:K is 1:2.

$\text{Moles of H}_{2} = \text{0.141 mol K} \times \dfrac{\text{1 mol H}_{2}}{\text{1 mol K}} = \text{0.0703 mol H}_{2}$

From HBr:

The molar ratio of H₂:HBr is 3:2.

$\text{Moles of H}_{2} = \text{0.049.93 mol HBr } \times \dfrac{\text{1 mol H}_{2}}{\text{1 mol HBr}} = \text{0.024 97 mol H}_{2}$

(iii) Identify the limiting reactant

HBr is the limiting reactant because it gives the smaller amount of NH₃.

b) Excess reactant

The excess reactant is K.

c) Mass of H₂

$\text{Mass of H}_{2} = \text{0.024 97 mol H}_{2} \times \dfrac{\text{2.016 g H}_{2}}{\text{1 mol H}_{2}} = \textbf{0.0503 g H}_{2}\\ \text{The mass of hydrogen is $\large \boxed{\textbf{0.0503 g}}$ }$

3 0

3 years ago

The order of a reaction Z1) is the product of the powers to which the reactant concentrations are raised in the rate law. Z2) ca

irinina [24]

Explanation:

The Order of Reaction refers to the power dependence of the rate on the concentration of each reactant.

The overall order of reaction is the sum of the individual orders of reaction with respect to the reactants.

Rate = k [A]²[B]¹

In the rate law above, the rate is second order with respect to A and first order with respect to B. The overall order of reaction is a third order reaaction given as; 2+ 1 = 3

6 0

4 years ago

Question 1 of 30

Ksivusya [100]

The answer will be A

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3 years ago

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Which quantity is equivalent to 39 grams of LiF?

Nutka1998 [239]

I think that it is 1.5 mole it might not be

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