Question

Which quantity is equivalent to 39 grams of LiF?

Answer 1

I think that it is 1.5 mole it might not be

Answer 2

Answer:

This question is incomplete, the completed question is below.

• Which quantity is equivalent to 39 grams of LiF?

(a) 1.0 mole  

(b) 2.0 mole  

(c) 0.50 mole

(d) 1.5 mole

The correct option is d

Explanation:

LiF is Lithium flouride. Lithium (Li) has a molar mass of 7 g/mol while flourine (F) has a molar mass of 19 g/mol. Hence, 1 mole of LiF will be

7 + 19 = 26 g/mol

If 1 mole of LiF = 26g,

X mole of LiF = 39g

When you cross multiply, you will have

X mole x 26g = 1 mole x 39g

make X the subject and you will have

X mole = 1 mole x 39g/26g

X mole = 1.5 mole

Hence, 1.5 mole of LiF is equivalent to 39 grams of LiF