The answer is 2,3,4,5 hope that helps
Answer:
it is 2/1
Step-by-step explanation:
What you're seeing here is 12 being multiplied by its reciprocal. 12 * 1/12 = 1. This is an example of a multiplicative inverse; a multiplicative inverse is when you multiply a number by its reciprocal (1 over the number).
The vertical asymptote of the function that are illustrated in the calculus and the function y = 3cot(1/2x) - 4 will be:
B. x = 0
C. x = +-2π
<h3>How to illustrate the information?</h3>
It should be noted that the function that's given from the information illustrated is given as:
y = 3 for (x/2) - 4
It should be noted that there is no phase shift and the period is 2π.
It should be noted that the vertical asymptote will be x = 3πn where no is represented as the integer at n = 0, 1, and -1.
Therefore, the vertical asymptote of the function that are illustrated in the calculus and the function y = 3cot(1/2x) - 4 will be x = 0 and x = +2π.
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Answer:
L.S = R.S ⇒ Proved down
Step-by-step explanation:
Let us revise some rules in trigonometry
- sin²α + cos²α = 1
- sin2α = 2 sin α cosα
- cscα = 1/sinα
To solve the question let us find the simplest form of the right side and the left side, then show that they are equal
∵ L.S = csc2α + 1
→ By using the 3rd rule above
∴ L.S =
+ 1
→ Change 1 to 
∴ L.S =
+ 
→ The denominators are equal, then add the numerators
∴ L.S = 
∵ R. S =
∵ (sinα + cosα)² = sin²α + 2 sinα cosα + cos²α
∴ (sinα + cosα)² = sin²α + cos²α + 2 sinα cosα
→ By using the 1st rule above, equate sin²α + cos²α by 1
∴ (sinα + cosα)² = 1 + 2 sinα cosα
→ By using the 2nd rule above, equate 2 sinα cosα by sin2α
∴ (sinα + cosα)² = 1 + sin2α
→ Substitute it in the R.S above
∴ R. S = 
∵ L.S = R.S
∴ csc 2α + 1 =