Answer:
The equilibrium pressure of HCl is 5.40 atm
Explanation:
Kc = [HCl]^2/[H2][Cl2]
Initial pressure of H2 = 3.46 atm and Cl2 = 3.46 atm
Let the equilibrium pressure of HCl be y
From the equation of reaction, mole ratio of H2 to HCl is 1:2, equilibrium pressure of H2 is (3.46 - 0.5y)
Also, from the y of reaction, mole ratio of Cl2 to HCl is 1:2, equilibrium pressure of Cl2 is (3.46 - 0.5y)
Kc = 50.1
50.1 = y^2/(3.46 -y)(3.46 - y)
50.1(11.9716 - 3.46y + 0.25y^2) = y^2
12.525y^2 - 173.346y + 599.77716 = y^2
11.525y^2 - 173.346y + 599.77716 = 0
y^2 - 15.04y + 52.04 = 0
The value of y is obtained using the quadratic formula
y = [15.04 - (sqrt (-15.04^2 - 4×1×52.04))] ÷ 2(1) = (15.04 - 4.25) ÷ 2 = 10.79 ÷ 2 = 5.40 atm (to 2 decimal places)
Answer:
It will take 77.8 seconds for 95% of sample to react
Explanation:
As the given reaction obeys 1st order therefore-
![[N_{2}O_{5}]=[N_{2}O_{5}]_{0}\times (\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}](https://tex.z-dn.net/?f=%5BN_%7B2%7DO_%7B5%7D%5D%3D%5BN_%7B2%7DO_%7B5%7D%5D_%7B0%7D%5Ctimes%20%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7B%5Cfrac%7Bt%7D%7Bt_%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7D)
Where ![[N_{2}O_{5}]](https://tex.z-dn.net/?f=%5BN_%7B2%7DO_%7B5%7D%5D)
is the concentration of 
after "t" time, ![[N_{2}O_{5}]_{0}](https://tex.z-dn.net/?f=%5BN_%7B2%7DO_%7B5%7D%5D_%7B0%7D)
is the initial concentration of and 
is half life
Here, ![\frac{[N_{2}O_{5}]}{[N_{2}O_{5}]_{0}}=\frac{100-95}{100}=0.05](https://tex.z-dn.net/?f=%5Cfrac%7B%5BN_%7B2%7DO_%7B5%7D%5D%7D%7B%5BN_%7B2%7DO_%7B5%7D%5D_%7B0%7D%7D%3D%5Cfrac%7B100-95%7D%7B100%7D%3D0.05)
and 
So, 
or, 
So, it will take 77.8 seconds for 95% of sample to react
Answer:
13.2 g of gold
Explanation:
We'll begin by converting 5.25 L to ft³.
This can be obtained as follow:
Recall:
1 L = 0.0353 ft³
Therefore,
5.25 L = 5.25 × 0.0353
5.25 L = 1.85×10¯¹ ft³
From the question given above,
2.45 g of gold is present in 5.25 L ( i.e 1.85×10¯¹ ft³) of soil.
Therefore, Xg of gold will be present in 1 ft³ of soil i.e
Xg of gold = 2.45/1.85×10¯¹
Xg of gold = 13.2 g
Therefore, 13.2 g of gold is present in 1 ft³ of the soil.
The product is magnesium sulfate plus hydrogen gas,as per this equation:
<span>Mg + H2SO4 = MgSO4 + H<span>2(g)</span></span>
Answer:
.
Explanation:
-Synthesis reactions are reactions that appear when two distinct atoms or molecules engage to structure a specific molecule or compound. Most of the time, when a synthesis response occurs, electricity is launched and the response is exothermic. However, an endothermic consequence is additionally possible.
-A decomposition response starts offevolved from a single substance and produces extra than one substance; that is, it decomposes. One substance as a reactant and greater than one substance as the merchandise is the key attribute of a decomposition reaction. For example, in the decomposition of sodium hydrogen carbonate (also recognized as sodium bicarbonate)
-A single-replacement response (sometimes referred to as a single-displacement reaction) is a chemical response in which one aspect is substituted for every other factor in a compound, producing a new aspect and a new compound as merchandise
-A double-replacement response (sometimes referred to as a double-displacement reaction) takes place when components of two ionic compounds are exchanged, making two new compounds. A attribute of a double-replacement equation is that there are two compounds as reactants and two distinctive compounds as product
-A combustion response happens when a reactant combines with oxygen, many instances from the atmosphere, to produce oxides of all different factors as products; any nitrogen in the reactant is transformed to elemental nitrogen, N2. Many reactants, referred to as fuels, incorporate normally carbon and hydrogen atoms, reacting with oxygen to produce CO2 and H2O
