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aleksley [76]
3 years ago
13

In the reaction below, 3.46 atm each of H2 and Cl2 were placed into a 1.00 L flask and allowed to react: H2(g) + Cl2(g) <=&gt

; 2 HCl(g) Given that Kc = 50.1, calculate the equilibrium pressure of HCl. Enter your answer to 2 decimal places.
Chemistry
1 answer:
Novosadov [1.4K]3 years ago
6 0

Answer:

The equilibrium pressure of HCl is 5.40 atm

Explanation:

Kc = [HCl]^2/[H2][Cl2]

Initial pressure of H2 = 3.46 atm and Cl2 = 3.46 atm

Let the equilibrium pressure of HCl be y

From the equation of reaction, mole ratio of H2 to HCl is 1:2, equilibrium pressure of H2 is (3.46 - 0.5y)

Also, from the y of reaction, mole ratio of Cl2 to HCl is 1:2, equilibrium pressure of Cl2 is (3.46 - 0.5y)

Kc = 50.1

50.1 = y^2/(3.46 -y)(3.46 - y)

50.1(11.9716 - 3.46y + 0.25y^2) = y^2

12.525y^2 - 173.346y + 599.77716 = y^2

11.525y^2 - 173.346y + 599.77716 = 0

y^2 - 15.04y + 52.04 = 0

The value of y is obtained using the quadratic formula

y = [15.04 - (sqrt (-15.04^2 - 4×1×52.04))] ÷ 2(1) = (15.04 - 4.25) ÷ 2 = 10.79 ÷ 2 = 5.40 atm (to 2 decimal places)

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1cc (cubic centimeter) and 1mL (milliliter) are the same volume. So, 25mL = 25cc

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Which of the following processes does our Sun and other stars in our galaxy use to create energy?
Usimov [2.4K]

Answer:

fusion reaction

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Explanation:

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5 0
3 years ago
Calculate the atomic mass of chromium it’s composition is 83.79% with a mass of 51.94 amu; 9.50% with a mass of 52.94 Amu; 4.35%
Elina [12.6K]

<span><span>Convert the percentages into decimals (you can do that by dividing the percent by 100), then multiply that by its corresponding mass to find its relative amount/ contribution to the atomic mass of chromium. After doing so, add all of the obtained values together to get the average mass.

</span> 83.79% = .08379
9.50% = .095
4.35% = .0435
2.36% = .0236

Average mass of chromium = 0.8379(51.94) + 0.095( 52.94) + 0.0435(49.95) + 0.0236(53.94)

Answer: 52amu

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8 0
3 years ago
According to the passage, which of the following would cause milk to go bad?
olga_2 [115]

Answer:

the answer D) will cause milk to go bad

8 0
3 years ago
Read 2 more answers
Be sure to answer all parts. Express the rate of reaction in terms of the change in concentration of each of the reactants and p
Tanzania [10]

Answer :  The [H] is increasing at the rate of 0.36 mol/L.s

Explanation :

The general rate of reaction is,

aA+bB\rightarrow cC+dD

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}

\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}

\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}

\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}

Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

2D(g)+3E(g)+F(g)\rightarrow 2G(g)+H(g)

The expression for rate of reaction :

\text{Rate of disappearance of }D=-\frac{1}{2}\frac{d[D]}{dt}

\text{Rate of disappearance of }E=-\frac{1}{3}\frac{d[E]}{dt}

\text{Rate of disappearance of }F=-\frac{d[F]}{dt}

\text{Rate of formation of }G=+\frac{1}{2}\frac{d[G]}{dt}

\text{Rate of formation of }H=+\frac{d[H]}{dt}

\text{Rate of reaction}=-\frac{1}{2}\frac{d[D]}{dt}=-\frac{1}{3}\frac{d[E]}{dt}=-\frac{d[F]}{dt}=+\frac{1}{2}\frac{d[G]}{dt}=+\frac{d[H]}{dt}

Given:

-\frac{d[D]}{dt}=0.18mol/L.s

As,  

-\frac{1}{2}\frac{d[D]}{dt}=+\frac{d[H]}{dt}=0.18mol/L.s

and,

+\frac{d[H]}{dt}=2\times 0.18mol/L.s

+\frac{d[H]}{dt}=0.36mol/L.s

Thus, the [H] is increasing at the rate of 0.36 mol/L.s

5 0
3 years ago
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