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olya-2409 [2.1K]
3 years ago
14

What is the product when magnesium reacts with sulfuric acid? mg(s) h2so4(aq) →what is the product when magnesium reacts with su

lfuric acid?mg(s) h2so4(aq) →
Chemistry
2 answers:
neonofarm [45]3 years ago
8 0

Explanation:

When magnesium reacts with sulfuric acid then it results in the formation of magnesium sulfate along with evolution of hydrogen gas.

The chemical reaction equation for the reaction is as follows.

Mg(s) + H_{2}SO_{4} \rightarrow MgSO_{4}(aq) + H_{2}(g)

This reaction is a single displacement reaction as magnesium has displaced hydrogen from sulfuric acid.

lions [1.4K]3 years ago
3 0
The product is magnesium sulfate plus hydrogen gas,as per this equation:

<span>Mg + H2SO4 = MgSO4 + H<span>2(g)</span></span>

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The enthalpy change for converting 1.00 mol of ice at -50.0 ∘c to water at 60.0∘c is ________ kj. the specific heats of ice, wat
guajiro [1.7K]
First, we have to get:

1- The heat required to increase T of ice from -50 to 0 °C:

according to q formula:

q1 = m*C*ΔT

when m is the mass of ice = mol * molar mass

                                             =  1 mol * 18 mol/g

                                            = 18 g

and C is the specific heat capacity of ice = 2.09 J/g-K

and ΔT change in temperature = 0- (-50) = 50°C

by substitution:

∴q1 = 18 g * 2.09 J/g-K *50°C

       = 1881 J = 1.881 KJ

2- the heat required to melt this mass of ice is :

q2 = n*ΔHfus 

when n is the number of moles of ice = 1 mol

and ΔHfus = 6.01 KJ/mol

by substitution:

q2 = 1 mol * 6.01 KJ/mol

     = 6.01 KJ

3- the heat required to increase the water temperature from 0°C to 60 °C is:

q3 = m*C*ΔT

when m is the mass of water = 18 g 

C is the specific heat capacity of water = 4.18 J/g-K

ΔT is the change of Temperature of water = 60°C - 0°C = 60°C

by substitution:

∴q3 = 18 g * 4.18 J/g-K * 60°C

      = 4514 J = 4.514 KJ

∴the total change of enthalpy = q1+q2+q3

                                                  = 1.881 KJ  +6.01 KJ + 4.514 KJ

                                                  = 12.405 KJ


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Neon belongs to 2nd Period & 18th Group
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Answer:

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