How many integers between 199 and 599 are multiple of 3
2 answers:
A.P. series would be: 201, 204, 207 .... 597
Here, a = 201, d = 3, l = 597
Now, l = a + (n - 1) d
597 = 201 + (n - 1)3
597 - 201 = 3n - 3
396 + 3 = 3n
n = 399/3
n = 133
In short, Your Answer would be 133
Hope this helps!
Fabulous question!
1st determine the entire sum of integers from 199 to 599
599 - 199 = 400
3x = 400
x = 133 integer approx
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Answer:
Factoring
Step-by-step explanation:
x^2 + 7x = x(x + 7) = 0
So
x = 0 or x = -7
Any number times 0 equals 0
I couldn’t really understand the question but i did 4squared + 3r(1) - 7(1)squared and i got -33 + 3r
