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butalik [34]
3 years ago
15

How many integers between 199 and 599 are multiple of 3

Mathematics
2 answers:
Reptile [31]3 years ago
8 0
A.P. series would be: 201, 204, 207 .... 597
Here, a = 201, d = 3, l = 597

Now, l = a + (n - 1) d
597 = 201 + (n - 1)3
597 - 201 = 3n - 3
396 + 3 = 3n
n = 399/3
n = 133

In short, Your Answer would be 133

Hope this helps!

morpeh [17]3 years ago
6 0
Fabulous question!
1st determine the entire sum of integers from 199 to 599
599 - 199 = 400

3x = 400
x = 133 integer approx
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Step-by-step explanation:

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2 years ago
Please help me with my work
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3 years ago
On a coordinate plane, parallelogram H I J K is shown. Point H is at (negative 2, 2), point I is at (4, 3), point J is at (4, ne
nasty-shy [4]

HIJK is a parallelogram because the midpoint of both diagonals is

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Step-by-step explanation:

If (x , y) is the mid-point of a segment whose end points are (x_{1},y_{1})  and  (x_{2},y_{2})  then,

  • x=\frac{x_{1}+x_{2}}{2}
  • y=\frac{y_{1}+y_{2}}{2}

In a parallelogram, its diagonals intersect each other at their mid-points

that means its diagonals bisect each other

∵ HIJK is a quadrilateral

∵ HJ and IK are its diagonals

∵ H = (-2 , 2)

∵ J = (4 , -2)

- Find the mid point of HJ  

∵ M_{HJ}=(\frac{-2+4}{2},\frac{2+-2}{2})

∴ M_{HJ}=(\frac{2}{2},\frac{0}{2})

∴ M_{HJ}=(1,0)

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∴ M_{IK}=(\frac{2}{2},\frac{0}{2})

∴ M_{IK}=(1,0)

∴ The mid-point of IK is (1 , 0)

∵ The mid-points of HJ and IK are equal

∴ HJ and IK bisects each other

∴ HIJK is a parallelogram because its diagonals bisect each other

HIJK is a parallelogram because the midpoint of both diagonals is

(1 , 0), which means the diagonals bisect each other

Learn more:

You can learn more about parallelogram in brainly.com/question/6779145

#LearnwithBrainly

6 0
2 years ago
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