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Mandarinka [93]
3 years ago
15

A falcon flying at a height of 200 yards spots a sparrow flying at a height of 150 yards. The location of the sparrow makes an a

ngle of 40 from the horizontal line through the falcons location. What is that distance x between the falcon and the sparrow? Assume that the ground beneath the bird is level.
Mathematics
2 answers:
juin [17]3 years ago
8 0
Answer: The distance between the birds is about 77.78 yards.

This is a trigonometry problems, so it helps to draw a right triangle between the birds. The length between them is the hypotenuse and we have a angle of 40 degrees by the sparrow. The side opposite the sparrow is the difference in heights of the birds, 50 yards.

Therefore, we can write and solve the following sine relationship.

sin(40) =  50/x
0.6428 = 50/x
x = 77.78 <span />
garik1379 [7]3 years ago
5 0

Answer:78

Step-by-step explanation:

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The one-time fling! Have you ever purchased an article of clothing (dress, sports jacket, etc.), worn the item once to a party,
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(a)\ P(x = 0) = 0.2725

(b)\ P(x \ge 1) =0.7275

(c)\ P(x \le 2) = 0.8948

Step-by-step explanation:

Given

n = 8 --- 8 friends

p = 15\% --- proportion that one-time fling

This question is an illustration of binomial probability, and it is represented as:

P(X = x) = ^nC_x* p^x * (1 - p)^{n-x}

Solving (a): P(x = 0) --- None has done one time fling

P(x = 0) = ^8C_0* (15\%)^0 * (1 - 15\%)^{8-0}

P(x = 0) = 1* 1 * (1 - 0.15)^{8}

P(x = 0) = 0.85^8

P(x = 0) = 0.2725

Solving (b): P(x \ge 1)

To do this, we make use of compliment rule:

P(x = 0) + P(x \ge 1) =1

Rewrite as:

P(x \ge 1) =1 - P(x = 0)

P(x \ge 1) =1 - 0.2725

P(x \ge 1) =0.7275

Solving (c): P(x\le 2)--- Not more than 2 has one time fling

This is calculated as:

P(x\le 2) = P(x = 0) + P(x =1) + P(x = 2)

We have:

P(x = 0) = 0.2725

P(x = 1) = ^8C_1* (15\%)^1 * (1 - 15\%)^{8-1}

P(x = 1) = 8* (0.15) * (1 - 0.15)^7

P(x = 1) = 0.3847

P(x = 2) = ^8C_2* (15\%)^2 * (1 - 15\%)^{8-2}

P(x = 2) = 28* (0.15)^2 * (1-0.15)^6

P(x = 2) = 0.2376

So:

P(x\le 2) = P(x = 0) + P(x =1) + P(x = 2)

P(x \le 2) = 0.2725 + 0.3847 + 0.2376

P(x \le 2) = 0.8948

4 0
3 years ago
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