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Natali [406]
3 years ago
14

Officer Brimberry wrote 24 tickets for traffic violations last week, but only 3 tickets this week. What is the percent decrease?

Give your answer to the nearest tenth of a percent.
the percent decrece is %
Mathematics
1 answer:
-BARSIC- [3]3 years ago
4 0

Answer:

12.5%

Step-by-step explanation:

3/ 24

=.125

=12.5%

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ΔABC is dilated by a factor of 3 to produce ΔA'B'C'.
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Answer:

Option B

Step-by-step explanation:

Dilation does not change the value of angle.

so angle measurement should be same as before .

Angle A= 37

Scale factor is 3 so multiply length by 3

So A'C'= 3×5 =15

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Solve by factoring or finding square roots x^2-18x-40=0
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Step-by-step explanation:

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3 years ago
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Kool-aide is made from flavored powder and water, with the ratio of powder to water 3:2 based on weight. If 120g of flavored pow
MAXImum [283]

The given ratio of powder to water is 3:2 based on weight for Kool-aide. It is also given that 120g of flavored powder is needed for a certain amount of Kool-aide.

Let us assume that the amount of water (by weight) required to maintain the given ratio of 3:2 be represented by the letter x. Thus, from the given information we can conclude that:

\frac{Powder Weight}{Water Weight}=\frac{3}{2}=\frac{120}{x}

\therefore \frac{3}{2}=\frac{120}{x}

Cross-multiplying we get:

3x=240

\therefore x=\frac{240}{3}=80 grams.

Thus, the amount of water in grams in that Kool-aide is 80 grams.

5 0
3 years ago
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Miguel is making smoothies out of yogurt and juice to serve to his friends, and he needs to make 12 cups. The ratio of yogurt to
tester [92]
12 divided by 2 is 6. So he will need a 6 cups of yogurt
6 0
3 years ago
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Prove that sinA-sin3A+sin5A-sin7A/cosA-cos3A-cos5A+cos7A= cot2A
MAVERICK [17]
Write the left side of the given expression as N/D, where
N = sinA - sin3A + sin5A - sin7A
D = cosA - cos3A - cos5A + cos7A
Therefore we want to show that N/D = cot2A.

We shall use these identities:
sin x - sin y = 2cos((x+y)/2)*sin((x-y)/2)
cos x - cos y = -2sin((x+y)/2)*sin((x-y)2)

N = -(sin7A - sinA) + sin5A - sin3A
    = -2cos4A*sin3A + 2cos4A*sinA
    = 2cos4A(sinA - sin3A)
    = 2cos4A*2cos(2A)sin(-A)
    = -4cos4A*cos2A*sinA

D = cos7A + cosA - (cos5A + cos3A)
   = 2cos4A*cos3A - 2cos4A*cosA
   = 2cos4A(cos3A - cosA)
   = 2cos4A*(-2)sin2A*sinA
   = -4cos4A*sin2A*sinA

Therefore
N/D = [-4cos4A*cos2A*sinA]/[-4cos4A*sin2A*sinA]
       = cos2A/sin2A
      = cot2A

This verifies the identity.
4 0
3 years ago
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