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Sveta_85 [38]
4 years ago
6

How do i set up a RAID 1 array?​

Computers and Technology
1 answer:
KiRa [710]4 years ago
3 0

are you using windows? linux? mac?

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Define the following:-<br><br>1) cryptography<br><br>2) Quantum Cryptography​
Readme [11.4K]
1.) the art of writing or solving codes.
2.) the science of exploiting quantum mechanical properties to perform cryptographic tasks.

hope this helps :)
8 0
3 years ago
Read 2 more answers
Memory unit is amount of data that can be stored in a storage unit true or false​
vladimir1956 [14]

Answer:

amount of data and the researcher in a bit and I'll get you can use my card if I'm going well for us the best part is a copy sir pasenya the same thing I

4 0
3 years ago
I have this assignment due TONIGHT BEFORE 10PM! Please help. 50 points for whoever will help!! Here is the assignment.
saveliy_v [14]

Answer:

# include <iostream.h>

# include <conio.h>

using namespace std;

int generatelist ( int z[]);

int addlist(int x []; int y []);

int mullist(int x []; int y []);

int displayList(int z[]);

main()

{

int a[10] , b[10], add[10], mul[10];

cout<<"Enter value in array a";

generatelist(a[10]);

cout<<"Enter value in array b";

generatelist(b[10]);

for (int i=0; i<=9; i++)

{

add[i]=addlist( a[i], b[i]);

cout<<"sum of list = "<< add[i];

}

for (int i=0; i<=9; i++)

{

mul[i]=mullist( a[i], b[i]);

cout<<"multiplication of list = "<< mul[i];

}

for (int i=0; i<=9; i++)

{

displayList(a[i]);

}

for (int i=0; i<=9; i++)

{

displayList(b[i]);

}

for (int i=0; i<=9; i++)

{

displayList(add[i]);

}

for (int i=0; i<=9; i++)

{

displayList(mul[i]);

}

getch();

}

int generatelist ( int z[])

{

for (int j=0 ; j<=9 ; j++)

{

cin>>z[j];

return z[j]

}

}

int addlist(int x []; int y [])

{

int add

add=x+y;

return add;

}

int mullist(int x []; int y [])

{

int mul

mul=x*y;

return mul;

}

int displayList(int z[]);

{

for(int i=0; i<=9;i++)

cout << z[i]

}

7 0
4 years ago
A drowsy cat spots a flowerpot that sails first up and then down past an open window. The pot is in view for a total of 0.50 sec
GaryK [48]

Answer:

2.342m

Explanation:

Given

Time = 0.5 s

Height of Window = 2m

Because the pot was in view for a total of 0.5 seconds, we can assume that it took the cat 0.25 seconds to go from the bottom of the window to the top

Using this equation of motion

S = ut - ½gt²

Where s = 2

u = initial velocity = ?

t = 0.25

g = 9.8

So, we have.

2 = u * 0.25 - ½ * 9.8 * 0.25²

2 = 0.25u - 0.30625

2 + 0.30625 = 0.25u

2.30625 = 0.25u

u = 2.30625/0.25

u = 9.225 m/s ------------ the speed at the bottom of the pot

Using

v² = u² + 2gs to calculate the height above the window

Where v = final velocity = 0

u = 9.225

g = 9.8

S = height above the window

So, we have

0² = 9.225² - 2 * 9.8 * s

0 = 85.100625 - 19.6s

-85.100625 = -19.6s

S = -85.100625/19.6

S = 4.342

If 4.342m is the height above the window and the window is 2m high

Then 4.342 - 2 is the distance above the window

4.342 - 2 = 2.342m

6 0
3 years ago
The K-Means algorithm terminates when:_______
gavmur [86]

Answer:

b. the cluster centers for the current iteration are identical to the cluster centers for the previous iteration.

Explanation:

K-mean algorithm is one of the mot widely used algorithm for partitioning into groups of k clusters. This is done by partitioning observations into clusters which are similar to each other. When using k-mean algorithm, each of the different clusters are represented by their centroid and each point are placed only in clusters in which the point is close to cluster centroid.

The K-Means algorithm terminates when the cluster centers for the current iteration are identical to the cluster centers for the previous iteration.

7 0
4 years ago
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