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Elena-2011 [213]
4 years ago
12

Identify the domain and range of the relation. Use a

Mathematics
1 answer:
vagabundo [1.1K]4 years ago
7 0

Answer:

Domain = {3,4,9}

Range = {2, 6, 8, 9.5}

Given relation is NOT a function.

Step-by-step explanation:

Given relation is relation is ((9,6), (3,8),(4,9.5), (9,2)}.

Now we need to determine if given relation is a function or not.

We also need to find the domain and range.

((9,6), (3,8),(4,9.5), (9,2)}

​Domain is basically the collection of x-values

So Domain = {3,4,9}

Range is basically the collection of y-values

So Range = {2, 6, 8, 9.5}

Since given relation contains repeated x-value "9".

So the given relation is NOT a function.

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3 years ago
Why did I get it wrong ? I’m finding constant B and idk what’s wrong with my step.
Klio2033 [76]

Answer:

\large \boxed{\sf \ \ A=5, \ \ B=-13 \ \ }

Step-by-step explanation:

Hello,

What you did is correct...

(Ax-3)(x-2)=5x^2+Bx+6\\\\\text{*** we develop the left side ***}\\\\Ax^2+(-2A-3)x+6=5x^2+Bx+6

... and you found A by identifying the term in x^2 to get A = 5, right?

<u>What about the other terms?</u>

<u />

We can then identify the like terms:

>>> term in x^2\\

   A = 5

>>> term in x

   -2A+3=B

>>> constant term

   6 = 6

As we know that A=5 it means that B = -2*5-3=-13

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0
4 years ago
Read 2 more answers
Evaluate (1/2^-2) + 1/2
Yuki888 [10]
It would be 4.5. Hope this helps!
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