All categories

3 years ago

A car rental company charges an initial fee plus a constant fee per kilometer driven.

Mathematics

1 answer:

leva [86]3 years ago

3 0

Answer:

$120

Step-by-step explanation:

constant fee = (204-183) /(140-105)

= 21/35 = $0.6 per km

so, initial fee =

183 - (105 × 0.6)

= 183 - 63

= 120

You might be interested in

A couple want to buy a house that costs $542 000. They pay a 20% deposit and borrow the rest of

Tanya [424]

Answer:

$146.00 a month I hope that's what you're look for

Step-by-step explanation:

go to Khan academy they give free math explainations

6 0

1 year ago

A first number plus twice a second number is 9. twice the first number plus the second totals 33. find the numbers.

Alla [95]

First number: x = 19
Second number: Y = -5

x + 2y = 9
2x + y = 33

3 0

2 years ago

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distri

nlexa [21]

Answer:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

For this case we want to test:

H0: Absenteeism is distributed evenly throughout the week

H1: Absenteeism is NOT distributed evenly throughout the week

We have the following data:

Monday Tuesday Wednesday Thursday Friday Saturday Total

12 9 11 10 9 9 60

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{60}{6}= 10$ and the expected value is the same for all the days since that's what we want to test.

now we can calculate the statistic:

$\chi^2 = \frac{(12-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(11-10)^2}{10}+\frac{(10-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(9-10)^2}{10}=0.8$

Now we can calculate the degrees of freedom (We know that we have 6 categories since we have information for 6 different days) for the statistic given by:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

4 0

3 years ago

Find the values of x and y using the figure below. Round your answer to the nearest integer.

11111nata11111 [884]

Answer:

x = 11

y = 17

Step-by-step explanation:

5y and (7y - 34) are vertical angles which means they're equal to each other:

5y = 7y - 34

5y - 7y = -34

-2y = -34

y = 17

(8x + 7) and (9x - 4) are also vertical angles:

8x + 7 = 9x - 4

8x - 9x = -4 - 7

-x = -11

x = 11

5 0

3 years ago

Find the value of tan theta if sin theta = 12/13 and theta is in quadrant 2

nadya68 [22]

In quadrant 2, $\sin\theta>0$ and $\cos\theta$ . Use the Pythagorean identity to establish that

$\sin^2\theta+\cos^2\theta=1\implies\cos\theta=-\sqrt{1-\sin^2\theta}=-\dfrac5{13}$

Then

$\tan\theta=\dfrac{\sin\theta}{\cos\theta}=\dfrac{\frac{12}{13}}{-\frac5{13}}=-\dfrac{12}5$

7 0

3 years ago