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Elis [28]
3 years ago
13

A car rental company charges an initial fee plus a constant fee per kilometer driven.

Mathematics
1 answer:
leva [86]3 years ago
3 0

Answer:

$120

Step-by-step explanation:

constant fee = (204-183) /(140-105)

= 21/35 = $0.6 per km

so, initial fee =

183 - (105 × 0.6)

= 183 - 63

= 120

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write an equation in point-slope form of the line that passes through the point (-3,6) and has a slope of 5
RSB [31]

Answer:

y=5x + 21

Step-by-step explanation:

y=5x×b

6= -15+b

b=21

5 0
3 years ago
How many mL of medication are needed to last 10 days if the dose of medication is 2.5 tsp TID (three times a day)?
rjkz [21]

Answer:

369.7 mL of medication

Step-by-step explanation:

How many mL of medication are needed to last 10 days if the dose of medication is 2.5 tsp TID (three times a day)?

From the above question,

The dosage of the medication =

2.5 tsp 3 times a day

= 2.5 × 3 = 7.5 tsp per day.

Since

1 day = 7.5 tsp

10 days = x tsp

Cross Multiply

x = 10 × 7.5 tsp

x = 75 tsp of medication for 10 days.

Step 2

It is important to note that:

1 tsp = 4.929 mL

75 tsp = x mL

Cross Multiply

x = 75 × 4.929 mL

x = 369.669 mL of medication

Approximately = 369.7 mL of medication

7 0
2 years ago
Solve each equation for the<br> 1) g=C+a, for a
Artemon [7]
The answer for this question is A=g-c
6 0
2 years ago
Help me find the rate of change for these points listed here, and also write an equation:
valentinak56 [21]
54-2/0-3=-17,3=a
Y=-17,3x+54 b=54 because its the initial value of y when x =0
When x=1 y=36,7
When x=2 y=19,4
I juste replaced 1 in the equation and did the calculation with my calculator
4 0
2 years ago
What is an equation that relates weight on earth and weight on the moom
stellarik [79]
W=mg 

<span>Where: </span>

<span>Weight = mass * acceleration due to gravity </span>

<span>So let's say I want to work out my weight on the moon. I know I weigh about 70kg (which would be N), but I can't use that figure for the calculation on the moon. That is what I weigh on Earth, so let's look at the equation... </span>

<span>70kg = mass * 9.81m/s^2 </span>

<span>Where 9.81m/s^2 is the acceleration due to gravity on the surface on the earth. I want to get rid of that, so let's work out my mass by division; </span>

<span>70/9.81 = 7.14kg </span>

<span>I googled the acceleration of gravity on the Moon, which was = 1.6m/s^2 </span>

<span>Let's use that in the same equation W=mg </span>

<span>W = 7.14kg * 1.6m/s^2 = 11.42N

</span><span>On the Moon, you would weigh approximately one sixth of your weight on Earth, so if your bathroom scales tell you you weigh 120 pounds, there you would weigh 20 pounds.
</span>
<span>Moon`s gravitational pull is about one-sixth to the gravitational pull on earth hence weight on moon is about one-sixth of the weight on earth.</span>
8 0
3 years ago
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