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Advocard [28]
3 years ago
8

Mindy is driving 32mi / h as she nears an elementary school. A first grade student runs into the street after a soccer ball, and

Mindy reacts in about three -quarters of a second . What is her approximate reaction distance?
Mathematics
1 answer:
kifflom [539]3 years ago
8 0

Answer:

11 meters  is her approximate reaction distance.

Step-by-step explanation:

Speed of the car of Mindy = 32 mile/hour = \frac{32\times 1609.34 m}{3600 s}

1 mile = 1609.34 m

1 hour = 3600 seconds

Duration for her reaction last after student runs into street in front of her = \frac{3}{4} seconds

Distance covered three -quarters of a second = d

d=\frac{32\times 1609.34 m}{3600 s}\times \frac{3}{4} s

d = 10.73 m ≈ 11 m

11 meters  is her approximate reaction distance.

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I NEED HELP ASAP....
LUCKY_DIMON [66]

You're told there is a 10th degree polynomial. There are four roots of multiplicity 1 and one of multiplicity 2 (a double root).

Anytime there is a root of multiplicity 1 of a polynomial, its graph crosses the x-axis at that root. Anytime there is one of multiplicity 2, it means that we count the root twice and the graph has a tangency point.

The degree of a polynomial tells you how how many roots it has. Ours is degree 10, so it has ten roots. We have the four roots of multiplicity 1 and the one of multiplicity two, for a total of 6. (four and two).

So there are six real roots.

The rest of the roots are imaginary and non-real, and 10 - 6 = 4.  So there are four imaginary roots.


Thus choice C is best.

3 0
3 years ago
Simplify.
Dominik [7]

Simplify: [{y^(2/7)}/{y^(1/2)}]

Since, [{a^(p/q)}/{a^(r/s)}] = a^{(p/q)-(r/s)}

Where,

  • a = p
  • p/q = 2/7 and
  • r/s = 1/2

so,

= y^{(2/7)-(1/2)}

Take the LCM of denominator i.e.,2 & 7 is 14.

= y^{(2*2 - 1*7)/14}

= y^{(4-7)/14}

= y^(-3/14) Ans.

<u>read</u><u> </u><u>more similar</u><u> questions</u><u>:</u> Which equation can be simplified to find the inverse of y = x2 – 7? a: x=y ^ 2 - 1/7 b: 1/x = y^2 - 7 c: x = y^2 – 7 d: –x = y^2 – 7..

brainly.com/question/2396514?referrer

6 0
2 years ago
Will Give Brainliest
PtichkaEL [24]
Surface area is taking the area of each face and adding it together. The equation is 2lw + 2hw + 2hl. So, for example, you'd take the length and the width to the find the area of the top. Multiply this by 2 to find the top AND the bottom. You need to end with 6 sides and all these together to find your surface area.
8 0
4 years ago
Please help me to prove this!<br>I need is no.(c). So, please help me do it.<br>​
zloy xaker [14]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = 90°                  → A + B = 90° - C

                                                     → C = 90° - (A + B)

Use the Double Angle Identity:      cos 2A = 1 - 2 sin² A

                                                       → sin² A = (1 - cos 2A)/2

Use Sum to Product Identity: cos A + cos B = 2 cos [(A + B)/2] · cos [(A - B)/2]

Use the Product to Sum Identity: cos (A - B) - cos (A + B) = 2 sin A · sin B

Use the Cofunction Identities:      cos (90° - A) = sin A

                                                       sin (90° - A) = cos A

<u>Proof LHS → RHS:</u>

LHS:                       sin² A + sin² B + sin² C

\text{Double Angle:}\qquad \dfrac{1-\cos 2A}{2}+\dfrac{1-\cos 2B}{2}+\sin^2 C\\\\\\.\qquad \qquad \qquad =\dfrac{1}{2}\bigg(2-\cos 2A-\cos 2B\bigg)+\sin^2 C\\\\\\.\qquad \qquad \qquad =1-\dfrac{1}{2}\bigg(\cos 2A+\cos 2B\bigg)+\sin^2 C

\text{Sum to Product:}\quad 1-\dfrac{1}{2}\bigg[2\cos \bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A-2B}{2}\bigg)\bigg]+\sin^2 C\\\\\\.\qquad \qquad \qquad =1-\cos (A+B)\cdot \cos (A-B)+\sin^2 C

Given:                1 - cos (90° - C) · cos (A - B) + sin² C

Cofunction:       1 - sin C · cos (A - B) + sin² C

Factor:               1 - sin C [cos (A - B) + sin C]

Given:                1 - sin C[cos (A - B) - sin (90° - (A + B))]

Cofunction:       1 - sin C[cos (A - B) - cos (A + B)]

Sum to Product:       1 - sin C [2 sin A · sin B]

                            = 1 - 2 sin A · sin B · sin C

LHS = RHS: 1 - 2 sin A · sin B · sin C = 1 - 2 sin A · sin B · sin C   \checkmark

6 0
3 years ago
4. Explain the difference between (-5)² and<br>-5²​
blsea [12.9K]

Answer:

the first one you have is a negative and 5-5-5-5-5

then same for other but oppoiste

Step-by-step explanation:

7 0
4 years ago
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