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Simora [160]
3 years ago
14

A rectangular page is to contain 32 square inches of print. The margins at the top and bottom of the page are to be 2 inches wid

e. The margins on each side are to be 1 inch wide. Find the dimensions of the page that will minimize the amount of paper used. (Let x represent the width of the page and let y represent the height.)
Mathematics
1 answer:
Helen [10]3 years ago
8 0
Gggggggggggvvgvvvvvbnjhhhbcse
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64 POINTS AWARDED, PLEASE ANSWER ASAP!!!!!
antoniya [11.8K]

Answer:

Area of rectangle = 40 square units

Step-by-step explanation:

<u>Points to remember</u>

<u>Distance formula</u>

Length of a line segment with end points (x₁, y₁) and (x₂, y₂) is given by,

Distance = √[(x₂ - x₁)² + (y₂ - y₁)²]

Area of rectangle = Length * Breadth

<u>To find the length and breadth</u>

Here a rectangle with vertices at (7, 3), (12, 3), (12, 11), and (7, 11)

Length1 =  √[(x₂ - x₁)² + (y₂ - y₁)²]

√[(12 - 7)² + (3 - 3)²] = √5² = 5

Length2 =  √[(x₂ - x₁)² + (y₂ - y₁)²]

√[(12 - 12)² + (11 - 3)²] = √8² = 8 units

Therefore Length of rectangle = 8 and  

Breadth of rectangle = 5 units

<u>To find the area of rectangle</u>

Area = Length * Breadth

  = 8 * 5 =  40 square units

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~**Will mark brainliest **~<br> For the correct answers to all three questions
aleksandr82 [10.1K]

a)

\dfrac{42}{65}\cdot\dfrac{25}{36}\cdot\dfrac{26}{49}=\dfrac{2\cdot3\cdot7}{5\cdot13}\cdot\dfrac{5\cdot5}{2\cdot2\cdot3\cdot3}\cdot\dfrac{2\cdot13}{7\cdot7}=\dfrac{7}{13}\cdot\dfrac{5}{2\cdot3}\cdot\dfrac{2\cdot13}{7\cdot7}=\\\\\\=\dfrac{1}{1}\cdot\dfrac{5}{2\cdot3}\cdot\dfrac{2}{7}=\dfrac{5}{3}\cdot\dfrac{1}{7}=\dfrac{5}{21}

b)

\dfrac{21}{32}\cdot\dfrac{39}{120}\cdot\dfrac{40}{65}=\dfrac{21}{32}\cdot\dfrac{3\cdot13}{2\cdot2\cdot2\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot2\cdot5}{5\cdot13}=\\\\\\=\dfrac{3\cdot7}{32}\cdot\dfrac{13}{2\cdot2\cdot2\cdot5}\cdot\dfrac{2\cdot2\cdot2}{13}=\dfrac{21}{32}\cdot\dfrac{1}{5}\cdot\dfrac{1}{1}=\dfrac{21}{160}

c)

\dfrac{15}{90}\cdot\dfrac{36}{75}\cdot\dfrac{27}{42}=\dfrac{3\cdot5}{2\cdot3\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot3\cdot3}{3\cdot5\cdot5}\cdot\dfrac{3\cdot3\cdot3}{2\cdot3\cdot7}=\\\\\\=\dfrac{1}{2\cdot3}\cdot\dfrac{2\cdot2\cdot3}{5\cdot5}\cdot\dfrac{3\cdot3}{2\cdot7}=\dfrac{1}{1}\cdot\dfrac{2}{5\cdot5}\cdot\dfrac{3\cdot3}{2\cdot7}=\dfrac{1}{25}\cdot\dfrac{9}{7}=\dfrac{9}{175}

6 0
3 years ago
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