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Simora [160]
3 years ago
14

A rectangular page is to contain 32 square inches of print. The margins at the top and bottom of the page are to be 2 inches wid

e. The margins on each side are to be 1 inch wide. Find the dimensions of the page that will minimize the amount of paper used. (Let x represent the width of the page and let y represent the height.)
Mathematics
1 answer:
Helen [10]3 years ago
8 0
Gggggggggggvvgvvvvvbnjhhhbcse
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Select the expression that is equal to –10(4x – 5).
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Answer:

-2 (20x - 25)

Step-by-step explanation:

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Suppose a linear transformation Upper T : Bold Upper R squared right arrow Bold Upper R squared is formed by taking a rotation c
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All points on line x+y = 0 or x-y=0 will satisfy the transformation.

Step-by-step explanation:

Let (x, y) be the general such point.

Hence rotating it by 180 deg. counterclockwise will give us (-y,-x).

Reflecting (-y,-x) on x axis gives us (-y,x).

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All points on line x+y = 0 or x-y=0 will satisfy the transformation.

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3 years ago
Please help ASAP with this one too! Thanks!
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Hello,

y+3=-6(x+2)
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The equation of four lines are given. Identify which lines are perpendicular.
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Suppose that the amount of time T a customer spends in a bank is exponentially distributed with an average of 10 minutes. What i
Bad White [126]

Answer:

The probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes  is 0.6065.

Step-by-step explanation:

The random variable <em>T</em> is defined as the amount of time a customer spends in a bank.

The random variable <em>T</em> is exponentially distributed.

The probability density function of a an exponential random variable is:

f(x)=\lambda e^{-\lambda x};\ x>0

The average time a customer spends in a bank is <em>β</em> = 10 minutes.

Then the parameter of the distribution is:

\lambda=\frac{1}{\beta}=\frac{1}{10}=0.10

An exponential distribution has a memory-less property, i.e the future probabilities are not affected by any past data.

That is, <em>P</em> (<em>X</em> > <em>s</em> + <em>x</em> | <em>X</em> ><em> s</em>) = <em>P</em> (<em>X</em> > <em>x</em>)

So the probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes  is:

P (X > 15 | X > 10) = P (X > 5)

\int\limits^{\infty}_{5} {f(x)} \, dx =\int\limits^{\infty}_{5}  {\lambda e^{-\lambda x}} \, dx\\=\int\limits^{\infty}_{5}  {0.10 e^{-0.10 x}} \, dx\\=0.10\int\limits^{\infty}_{5}  {e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10}|^{\infty}_{5}\\=[-e^{-0.10 \times \infty}+e^{-0.10 \times 5}]\\=0.6065

Thus, the probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes  is 0.6065.

8 0
3 years ago
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