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tresset_1 [31]
3 years ago
8

Keeping the number of moles constant, what is the final pressure in atm if the temperature was cooled from -91.5°C to -239°C, th

e volume decreased from 3.41L to 3.3L and the original pressure was 3990 torr?
Change celcius to Kelvin.
Chemistry
1 answer:
GalinKa [24]3 years ago
7 0

Answer:

The answer to your question is:      P2 = 772.35 torr.

Explanation:

Data

P1 = 3990 torr.

V1 = 3.41 L

T1 = -91.5°C  = 181.5°K

P2 = ?

V2 = 3.3 L

T2 = -239°C = 34°K

Formula

             \frac{P1V1}{T1} = \frac{P2V2}{T2}P2 = \frac{P1V1T2}{T1V2}

                                 P2 = \frac{(3990)(3.41)(34)}{(181.5)(3.3)}[/tex]

                                 P2 = 462600.6 / 598.95

                                 P2 = 772.35 torr.

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The kinetic energy is related to the speed, such that the lower speed the lower kinetic energy.


Particles can translate and vibrate, in the case of gases and liquids, and only vibrate (in the case of solids).


As a substance is cooled the particles get closer and the motion (translation and vibration), slows down. You can see by the equation of the kinetic energy (KE):


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Answer:

The balanced chemical equation :

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Ca(OH)_2(s)+2HCl(aq)\rightarrow CaCl_2(aq)+2H_2O(l)

According to stoichiometry, when 1 mole of solid calcium hydroxide reacts with 1 mole of hydrochloric acid to gives 1 mole of aqueous calcium chloride and 1 mole of water.

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The chemical equation would be:

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