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tresset_1 [31]
3 years ago
8

Keeping the number of moles constant, what is the final pressure in atm if the temperature was cooled from -91.5°C to -239°C, th

e volume decreased from 3.41L to 3.3L and the original pressure was 3990 torr?
Change celcius to Kelvin.
Chemistry
1 answer:
GalinKa [24]3 years ago
7 0

Answer:

The answer to your question is:      P2 = 772.35 torr.

Explanation:

Data

P1 = 3990 torr.

V1 = 3.41 L

T1 = -91.5°C  = 181.5°K

P2 = ?

V2 = 3.3 L

T2 = -239°C = 34°K

Formula

             \frac{P1V1}{T1} = \frac{P2V2}{T2}P2 = \frac{P1V1T2}{T1V2}

                                 P2 = \frac{(3990)(3.41)(34)}{(181.5)(3.3)}[/tex]

                                 P2 = 462600.6 / 598.95

                                 P2 = 772.35 torr.

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Besides their shape, how does a 2p orbital differ from a 3d orbital? chegg.
Blababa [14]

Answer:

The 3p orbitals have the same general shape and are larger than 2p orbitals, but they differ in the number of nodes. You have probably noticed that the total number of nodes in an orbital is equal to n−1 , where n is the principal quantum number. Thus, a 2p orbital has 1 node, and a 3p orbital has 2 nodes.

5 0
2 years ago
The density of water at 4 degrees Celsius is 1.00 g/cm cubed at unknown object has density of 7.9 g/cm cubed would you expect it
NNADVOKAT [17]

Answer:

The object will be sank

Explanation:

In this case the object is more dense than water.

Density is the relationship between a certain amount of mass of matter and the volume that is being occupied by it.

The object occupies more volume, so it occupies more mass.

As the mass from the object is higher, the object will be sank because the weight is higher than the weight from the liquid.

If the object has a lower density than the water, it will float on it.

7 0
3 years ago
A 15.0 ml sample of gas at 10.0 degree Celsius and 760 torr changes to a pressure of 1252 torr at 35.0 degree Celsius. What is t
netineya [11]

Answer:

9.91 mL

Explanation:

Using the combined gas law equation as follows;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (torr)

P2 = final pressure (torr)

V1 = initial volume (mL)

V2 = final volume (mL)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

V1 = 15.0mL

V2 = ?

P1 = 760 torr

P2 = 1252 torr

T1 = 10°C = 10 + 273 = 283K

T2 = 35°C = 35 + 273 = 308K

Using P1V1/T1 = P2V2/T2

760 × 15/283 = 1252 × V2/308

11400/283 = 1252V2/308

Cross multiply

11400 × 308 = 283 × 1252V2

3511200 = 354316V2

V2 = 3511200 ÷ 354316

V2 = 9.91 mL

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Multiple them divided by 2.50
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What is a chemical reaction​. in your own words but be more detailed about what you say.
harkovskaia [24]

Answer:

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