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tresset_1 [31]
3 years ago
8

Keeping the number of moles constant, what is the final pressure in atm if the temperature was cooled from -91.5°C to -239°C, th

e volume decreased from 3.41L to 3.3L and the original pressure was 3990 torr?
Change celcius to Kelvin.
Chemistry
1 answer:
GalinKa [24]3 years ago
7 0

Answer:

The answer to your question is:      P2 = 772.35 torr.

Explanation:

Data

P1 = 3990 torr.

V1 = 3.41 L

T1 = -91.5°C  = 181.5°K

P2 = ?

V2 = 3.3 L

T2 = -239°C = 34°K

Formula

             \frac{P1V1}{T1} = \frac{P2V2}{T2}P2 = \frac{P1V1T2}{T1V2}

                                 P2 = \frac{(3990)(3.41)(34)}{(181.5)(3.3)}[/tex]

                                 P2 = 462600.6 / 598.95

                                 P2 = 772.35 torr.

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Answer:

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How are electrons excited in element?
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Explanation:

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When the energy is provided to the atom the electrons by absorbing the energy jump to the higher energy levels. This process is called excitation. The amount of energy absorbed by the electron is exactly equal to the energy difference of orbits.  For example if electron jumped from K to L it must absorbed the energy which is equal the energy difference of these two level. The excited electron thus move back to lower energy level which is K by releasing the energy.

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4 0
3 years ago
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Sergeeva-Olga [200]

Answer:

<h2>D) 6</h2>

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