Answer:
The maximum potential energy of the child will be maximum at the two end points.
The maximum kinetic energy of the <em>child </em>occurs at the lowest point of the swing.
The potential energy of the child depends on the displacement of the child.
P.E = mgh
The maximum height attained occurs at the two end points of her swing motion.
Thus, the maximum potential energy of the child will be maximum at the two end points.
The kinetic energy of the child depends on the velocity of the child
K.E = ¹/₂mv²
The maximum velocity of the swing occurs at the lowest point of the swing.
Thus, the maximum kinetic energy of the child occurs at the lowest point of the swing.
Hope this helps!
Answer:
molecular so number 3. ...
The answer to this ? is true
Answer:
Explanation:
From the statement of the problem,
B₂S₃
+ H₂O
→ H₃BO₃
+ H₂S
B₂S₃ + H₂O → H₃BO₃ + H₂S
We that the above expression does not conform with the law of conservation of mass:
To obey the law, we need to derive a balanced reaction equation:
Let us use the mathematical method to obtain a balanced equation.
let the balanced equation be:
aB₂S₃ + bH₂O → cH₃BO₃ + dH₂S
where a, b, c and d will make the equation balanced.
Conservating B: 2a = c
S: 3a = d
H: 2b = 3c + 2d
O: b = 3c
if a = 1,
c = 2,
b = 6,
2d = 2(6) - 3(2) = 6, d = 3
Now we can input this into our equation:
B₂S₃ + 6H₂O → 2H₃BO₃ + 3H₂S
B₂S₃
+ 6H₂O
→ 2H₃BO₃
+ 3H₂S