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makkiz [27]
3 years ago
11

Which best describes the function of the structure labeled y​

Chemistry
1 answer:
postnew [5]3 years ago
7 0

Answer:

Y is a gamma ray in a nuclear equation, which y equals 0.

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Life as we know it could not exist without water. All the chemical reactions of life occur in an aqueous solution. Water molecul
dusya [7]
A) At 0 C water forms ice but as mentioned above F) water's greatest density occurs at 4 C and it decreases below 4 C so ice is lighter than 4C water, thus, at 0C ice comes to surface and acts as insulator thereby preventing lower water from freezing.
5 0
2 years ago
The target diol is synthesized in one step from 1-methylcyclopentene, but your lab partner exhausted the supply of that alkene.
andrezito [222]

Answer:

The reagents are CH_{3}CH_{3}O^{-},OsO_{4},NaHSO_{3}and H_{2}O.

Explanation:

1-Methylenecyclopentene is treated with HBr form 1-bromo-1-methylcyclopentane, which is treated with strong base ethoxide ion and forms 1-methylcyclopent-1-ene.

This alkene is treated with osmium tetraoxide in the presence of sodium bisulfite to form target product.

The chemical reaction is as follows.

4 0
3 years ago
How did Moseley establish a more accurate periodic table?
Elenna [48]
Moseley  established a more accurate periodic table by closer determination of atomic numbers. Through the results of his measurements of the wavelengths of the X-ray spectral lines of a number of elements which showed that the ordering of the elements by atomic number. 
4 0
3 years ago
A solution of HNO3HNO3 is standardized by reaction with pure sodium carbonate. 2H++Na2CO3⟶2Na++H2O+CO2 2H++Na2CO3⟶2Na++H2O+CO2 A
Gemiola [76]

Answer:

(0,653±0,002) M of HNO₃

Explanation:

The reaction of standarization of HNO₃ with Na₂CO₃ is:

2 HNO₃ + Na₂CO₃ ⇒ 2 Na⁺ + H₂O + CO₂ + 2NO₃⁻

To obtain molarity of HNO₃ we need to know both moles and volume of this acid. The volume is (27,71±0,05) mL and to calculate the moles it is necessary to obtain the Na₂CO₃ moles and then convert these to HNO₃ moles, thus:

0,9585 g of Na₂CO₃ × ( 1 mole / 105,988 g) =

9,043×10⁻³ mol Na₂CO₃ × ( 2 moles of HNO₃ / 1 mole of Na₂CO₃) = 1,809×10⁻² moles of HNO₃

Molarity is moles divide liters, thus, molarity of HNO₃ is:

1,809×10⁻² moles / 0,02771 L = 0,6527 M of HNO₃

The absolute uncertainty of multiplication is the sum of relative uncertainty, thus:

ΔM = 0,6527M× (0,0007/0,9585 + 0,001/105,988 + 0,05/27,71) =

0,6527 M× 2,54×10⁻³ = 1,7×10⁻³ M

Thus, molarity of HNO₃ solution and its absolute uncertainty is:

(0,653±0,002) M of HNO₃

I hope it helps!

5 0
4 years ago
Observe the reaction between N2 and H2 to make NH3.
GarryVolchara [31]

Answer: , 4 molecules of ammonia, NH3(g) is produced; 2 molecules of ammonia, NH3(g) is produced respectively

Explanation:

The balanced equation is stated below N2(g) + 3H2(g) → 2NH3(g)

1 mole of N2(g) reacts with 3 moles of H2(g) to yield 2 moles of NH3(g)

1) If 2 molecules of N2 react, then the balanced equation will be

2N2(g) + 6H2(g) → 4NH3(g)

Thus, 4 molecules of ammonia, NH3(g) is produced

2) If 3 molecules of H2 react, then the balanced equation will be

N2(g) + 3H2(g) → 2NH3(g)

Thus, 2 molecules of ammonia, NH3(g) is produced

6 0
3 years ago
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