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natali 33 [55]
3 years ago
8

A gas has a pressure of 2.31 atm and occupies

Chemistry
1 answer:
jenyasd209 [6]3 years ago
4 0

Answer:

The pressure of the gas after getting compressed is 1.92 L.

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.  

The equation given by this law is:

P_1V_1=P_2V_2  (At constant temperature)

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=2.31 atm\\V_1=8 L\\P_2=?mmHg\\V_2=1.92 L

Putting values in above equation, we get:

2.31 atm\times 8 L=P_2\times 1.92 L

P_2=\frac{2.31 atm\times 8 L}{1.92 L}

P_2=9.625 atm

The pressure of the gas after getting compressed is 1.92 L.

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3 years ago
What will be the end product for each electrode after electrolysis if the solution is concentrated aqueous sodium chloride ?​
Eddi Din [679]

Answer:

Cathode: Hydrogen gas

Anode: Chlorine gas

Explanation:

① Write down the ions present in the electrolyte

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Anions: Cl⁻ , OH⁻

② Decide which ions are preferentially discharged.

These are the factors:

For the discharge of cations,

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(The lower the position of the cation in the reactivity series, the easier it is to be discharged)

For the discharge of anions,

- Concentration effect (look at this first)

(The more concentrated the ion, the easier for it to be discharged)

- If solution is not concentrated (dilute), look at the position of the anion on the electrochemical series.

(The lower the position of the anion on the electrochemical series, the easier of it to be discharged)

In this case:

For cations, H⁺ ions are selectively discharged at the cathode as its position is lower than Na⁺ in the reactivity series.

Anion: Cl⁻ ions, being more concentrated, are selectively discharged at the anode.

☆For electrolysis,

Cation at the cathode (-ve terminal)

Anion at the anode (+ve terminal)

In summary, here's what happened at each electrode:

<u>C</u><u>athode</u>

- H⁺ selectively discharged

- ionic half equation: 2H⁺ (aq) +2e⁻ → H₂ (g)

<u>Anode</u>

- Cl⁻ ions selectively discharged

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3 0
3 years ago
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Answer:

The mass of CO22 in total is 264 g.

The atomic mass for C is 12 g / mole.

The molar mass for CO22 is (12 + (2 × 16)) = 44 g / mole.

m C = (12 / 44) × 264 = 72 g

So, there are 72 g of C in 264 g of CO2

Explanation:

there's the answer have a good day.

4 0
3 years ago
How many moles of MgCl2 are there in 319 g of the compound?
Leokris [45]

Hey there!:

Molar mass MgCl2 = 95.2110 g/mol

So:

1 mole MgCl2 -------------- 95.2110 g

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moles MgCl2 = 319 * 1 / 95.2110

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=> 3.350 moles of MgCl2


Hope that helps!

3 0
3 years ago
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