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tangare [24]
3 years ago
13

Simplify the expression. 10^log10^9

Mathematics
1 answer:
satela [25.4K]3 years ago
3 0
Answer I got was 9, third option
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Solve the rational equation x divided by 6 equals x squared divided by quantity x minus 1 end quantity, and check for extraneous
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Answer:

x = 0 and x = \textrm{negative one fifth}

Step-by-step explanation:

Given:

The rational equation to solve is given as:

\frac{x}{6}=\frac{x^2}{x-1}


We use the cross multiplication rule and multiply the numerators one side with the denominators of the other side. Therefore,

x\times (x-1)=6\times x^2\\x^2-x=6x^2\\\textrm{Bringing all variables to the right side, we get:}\\6x^2-x^2+x=0\\5x^2+x=0\\x(5x+1)=0\\x=0\ or\ 5x+1=0\\x=0\ or\ x=-\frac{1}{5}


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Also, x=-\frac{1}{5} is also a solution as the equation's denominator is defined at that point.

So, no extraneous solution.

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