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swat32
3 years ago
10

Select the correct answer. There are four samples on a laboratory table. Sample A. is a hard crystalline solid, which does not b

reak easily. Sample B is a solid that readily dissolves in water. Sample C is a liquid that evaporates at room temperature. Sample D is a colored liquid that conducts electricity. Based on this information, which sample is most likely to be a covalent compound?
Chemistry
2 answers:
harkovskaia [24]3 years ago
8 0

Answer is C for Plato users.

german3 years ago
3 0

Answer: Option (C) is the correct answer.

Explanation:

A covalent compound is formed by sharing of electrons between two chemically combining atoms.

A covalent bond will always form between non-metals.

Some properties of covalent compounds are as follows.

  • Covalent compounds are brittle in nature. This means they tend to break easily.
  • Covalent compounds have low melting and boiling point.
  • These compounds are unable to conduct heat and electricity.
  • Covalent compounds generally do not dissolve in water.

As covalent compounds have low melting and boiling point so, it is possible that they evaporate at room temperature.

Thus, we can conclude that sample C is a liquid that evaporates at room temperature, most likely to be a covalent compound.

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A beaker is filled to the 500 mL mark with alcohol. What increase in volume (in mL) does the beaker contain when the temperature
Aliun [14]

Answer:

"1.4 mL" is the appropriate solution.

Explanation:

According to the question,

  • v_0=500
  • \alpha =1.12\times 10^{-4}
  • \Delta \epsilon = 25

Now,

Increase in volume will be:

⇒ \Delta V = \alpha\times v_0\times \Delta \epsilon

By putting the given values, we get

           =1.12\times 10^{-4}\times 500\times 25

           =1.12\times 10^{-4}\times 12500

           =1.4  \ mL

8 0
3 years ago
A 25.0-mL sample containing Cu2+ gave an instrument signal of 25.2 units (corrected for a blank). When exactly 0.500 mL of 0.027
irga5000 [103]

Answer:

The molar concentration of Cu²⁺ in the initial solution is 6.964x10⁻⁴ M.

Explanation:

The first step to solving this problem is calculating the number of moles of Cu(NO₃)₂ added to the solution:

C = \frac{n}{V} \\0.0275 = \frac{n}{0.0005} \\

n = 1.375x10⁻⁵ mol

The second step is relating the number of moles to the signal. We know the the n calculated before is equivalent to a signal increase of 19.9 units (45.1-25.2):

1.375x10⁻⁵ mol _________ 19.9 units

        x              _________  25.2 units

x = 1.741x10⁻⁵mol

Finally, we can calculate the Cu²⁺ concentration :

C = 1.741x10⁻⁵mol / 0.025 L

C = 6.964x10⁻⁴ M

7 0
3 years ago
What is acid sulfuric's function ?​
masya89 [10]

Answer:

The answer is below

Explanation:

Sulfuric acid is used for various purposes, some of which include the following:

1. It is used in the production of various manufactured goods.

2. It is used in the manufacturing of chemicals

3. It is also used in the making of fertilizer

4. It is used in the refining process of petroleum products

5. It is used in the processing of metals

3 0
3 years ago
What volume of H2 at STP, can be released by 42.7 g Zn in the equation: Zn + 2 HCl ————> H2 + ZnCl2
ehidna [41]

Answer:

0.86L.

Explanation:

1mol of Zn has mass of 65.39g . The amount of Zn is 2.5g65.39g/mol=0.038mol

7 0
2 years ago
Formula of <br> Al³⁺ and SO₄²⁻
Sergio039 [100]

Answer:

The formula of Al³⁺ and SO₄²⁻ is aluminum sulfate.

Explanation:

The formula for aluminum sulfate is Al₂(SO₄)₃. If we say in terms of ions. The ions are Al³⁺. It is a positive ion or the cation. Other ion is SO₄²⁻. It is sulfate ion. It is anion.

Aluminum sulphate is used in water purification and as a mordant in dyeing and printing textiles.

Hence, the formula of Al³⁺ and SO₄²⁻ is aluminum sulfate.

3 0
3 years ago
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