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Kipish [7]
3 years ago
11

How much force is needed to accelerate a 1245 kg car at a rate of 4.25 m/sec^2?

Physics
1 answer:
BartSMP [9]3 years ago
3 0

Answer:

F = 5291.25 N

Explanation:

F = Ma so 1245 times 4.25^2 ,, that equals 5291.25 N

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A Honda Civic Hybrid weighs about 3200 lb .
Usimov [2.4K]
3200÷0.22= 145.4545...N
(it is an infinite decimal)
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El medio ambiente y su relacion con la educacion fisica??
Whitepunk [10]

Answer:

La Educación Ambiental es un proceso educativo continuo que persigue hacer sensible, formar y modificar actitudes de forma objetiva sobre la realidad global del medio, tanto natural como social, con este trabajo consideramos que la asignatura de Educación Física en sí,

Explanation:

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2 years ago
A golf ball is dropped from rest from a height of 9.5m.  It hits the pavement then bounces back up rising  just 5.7 m before fal
Oksanka [162]

Answer: 3.4s

Explanation:

There are three stages in the motion of the ball, so you have to calculate the times for every stage.

1) Ball dropping from 9.5m: free fall

d = Vo + gt² / 2

Vo = 0 ⇒ d = gt² / 2 ⇒ t² = 2d / g = 2 × 9.5 m / 9.81 m/s² = 1.94 s²

⇒ t = √ (1.94 s²) = 1.39s

2) Ball rising 5.7m (vertical rise)

i) Determine the initial speed:

Vf² = Vo² - 2gd

Vf² = 0 ⇒ Vo² = 2gd = 2 × 9.81 m/s² × 5.7m = 111.8 m²/s²

⇒ Vo = 10.6 m/s

ii) time rising

Vf = Vo - gt

Vf = 0 ⇒ Vo = gt ⇒

t = Vo / g = 10.6 m/s / 9.81 m/s² = 1.08 s

3) Ball dropping from 5.7 m to 1.20m above the pavement (free fall)

i) d = 5.7m - 1.20m = 4.5m

ii) d = gt² / 2 ⇒ t² = 2d / g = 2 × 4.5 m / 9.81 m/s² = 0.92 s²

⇒ t = √ (0.92 s²) = 0.96s

4) Total time

t = 1.39s + 1.08s + 0.96s = 3.43s ≈ 3.4s

4 0
3 years ago
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Which is heavier?<br> A kilogram of steel? <br> or<br> A kilogram of feathers?
Dahasolnce [82]

Answer: below

Explanation: 1kg of steel is slightly heavier than 1 kg of feathers. 1 kg of feather will displace more air as the density of feather is very less comparitively. More the volume displaced more is the upthrust and less the apparent weight.

3 0
3 years ago
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Suppose you had 10 identical molecules enclosed by a box. At a given instant, one molecule has an energy of 100 Joules, and the
boyakko [2]

Answer:

A)   K_average = 1/20 m v², B) low entropy , C) entropy increases.

Explanation:

A) The kinetic energy of each molecule

         K = ½ m v²

The average kinetic energy is the sum of each kinetic energy among the number of them

        K_average = (½ m v² + 0 + 0 +) 10

        K_average = 1/20 m v²

B) Entropy is the sum of the states of each molecule, in this configuration there are only two states one with energy and the other with zero energy, so it is a system with low entropy.

       S = k ln W

  Where S is the entropy, k the Bolztmann constant, W the amount of state present in the system in this case is 2

C) Let's start by analyzing the entropy, as time goes by the molecule that is moving collides with the other molecules and transfers them some energy, so the other molecules move to a different state, after a little In time all the molecules will have the same energy, each one in a different state or volume, so the number of possible state increases to 10, so the entropy increases.

Now let's analyze what happens with the energy of the system, for this case we have two possibilities

- The system is isolated, therefore as it cannot exchange energy with the environment, the total energy remains constant even when the energy of each molecule can fluctuate.

- If the system is not isolated, it can exchange energy with the environment, therefore the total energy changes, depending on the difference in energy between the molecules and the environment

4 0
3 years ago
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