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SCORPION-xisa [38]
2 years ago
15

Which organism in the food chain is sometimes first level consumer and sometimes 2nd level

Physics
1 answer:
makkiz [27]2 years ago
7 0
I believe the answer is Mouse/Herbivore. It was a question in my old lab haha.

Hope this helped!!
~xox Melis
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What is acceleration?​
jasenka [17]

Answer:

the rate of change of velocity per unit of time.

3 0
2 years ago
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Help meeeeeeeeeeeeee! please show work! In a collision, Kara Less who was traveling at 11 m/s while texting in her 1300 kg car,
raketka [301]

The impulse experienced is -18,000 kg m/s

Explanation:

The impulse exerted on an object is equal to the change in momentum of the object. Mathematically:

I=\Delta p = m(v-u)

where

m is the mass of the object

v is the final velocity of the object

u is the initial velocity

\Delta p is the change in momentum

I is the impulse

In the collision in this problem,

m = 1300 kg is the mass of the car

u = 11 m/s is the initial velocity

v = -2.5 m/s is the final velocity (negative, since it is in the opposite direction)

Substituting, we find

I=(1300)(-2.5-11)=-17,550 kg m/s

So the closest choice is

-18,000 kg m/s

Learn more about impulse and change in momentum:

brainly.com/question/9484203

#LearnwithBrainly

7 0
3 years ago
A current in a wire increases from 2 a to 6 a. how will the magnetic field 0.01 m from the wire change? it increases to four tim
kotykmax [81]

Answer:

 It increases to three times it's original value.

Explanation:

B

4 0
2 years ago
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In an experiment, students measure the position x of a cart as a function of time t for a cart that starts at rest and moves wit
Minchanka [31]

Given :

Initial velocity , u = 0 m/s² .

To Find :

The acceleration of the cart.

Solution :

Since, acceleration is constant.

Using equation of motion :

x = ut + \dfrac{at^2}{2}\\\\x = \dfrac{at^2}{2}

Putting, t = 1 s  and x = 4 m in above equation, we get :

4 = \dfrac{a(1)^2}{2}\\\\a = 8 \  m/s^2

Therefore, the acceleration of the cart is 8 m/s².

5 0
3 years ago
A car traveling at 60km/h undergoes uniform acceleration at a rate of 2/ms^2 until is velocity reached 120km/h determine the dis
jenyasd209 [6]

Explanation:

Given that,

Initial speed of a car, u = 60 km/h = 16.67 m/s

Acceleration, a = 2m/s²

Final speed, v = 120 km/h = 33.33 m/s

We need to find the distance traveled and the time taken to make the distance.

acceleration = rate of change of velocity

a=\dfrac{v-u}{t}\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{33.33 -16.67 }{2}\\\\t=8.33\ s

let the distance be d.

d=\dfrac{v^2-u^2}{2a}\\\\d=\frac{33.33^{2}-16.67^{2}}{2(2)}\\\\d=208.25\ m

Hence, the distance traveled and the time taken to make the distance is 208.25 m and 8.33 seconds respectively.

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