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3 years ago

Which organism in the food chain is sometimes first level consumer and sometimes 2nd level

Physics

1 answer:

makkiz [27]3 years ago

7 0

I believe the answer is Mouse/Herbivore. It was a question in my old lab haha.

Hope this helped!!
~xox Melis

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Of all the radio waves, these have the shortest wavelengths and the the highest frequency?

Julli [10]

If by chance you mean any wave, the wave with the shortest wavelength/highest frequency is gamma rays.

4 0

3 years ago

To overcome the problems that blur images and don't provide the best resolution from Earth, astronomers have started using flexi

schepotkina [342]

Answer:

adaptive optics

Explanation:

simple

3 0

2 years ago

A) A mass spectrometer has a velocity selector that allows ions traveling at only one speed to pass with no deflection through s

KengaRu [80]

Answer:

(A). The speed of the ions is $1.2\times10^{6}\ m/s$

(B). The radius of curvature of a singly charged lithium ion is $2.0\times10^{6}\ m$

Explanation:

Given that,

Electric field = 60000 N/C

Magnetic field = 0.0500 T

(A). We need to calculate the velocity

For no deflection

$F_{E}=F_{B}$

$Eq=Bqv$

$v = \dfrac{E}{B}$

$v=\dfrac{60000}{0.0500}$

$v=1.2\times10^{6}\ m/s$

(B). We need to calculate the radius

Using magnetic force balance by centripetal force

$Bqv=\dfrac{mv^2}{r}$

$r=\dfrac{mv^2}{Bqv}$

Put the value into the formula

$r=\dfrac{1.16\times10^{-26}\times(1.2\times10^{6})^2}{0.0500\times1.6\times10^{-19}}$

$r=2.0\times10^{6}\ m$

Hence, (A). The speed of the ions is $1.2\times10^{6}\ m/s$

(B). The radius of curvature of a singly charged lithium ion is $2.0\times10^{6}\ m$

6 0

3 years ago

A solid cube of aluminum (density of 2.7 g/cm³) has a volume of 0.9 cm³. how many atoms are contained in the cube?

Reika [66]

Answer:

$0.542*10^{23}\ Aluminum\ Atoms$

Explanation:

$We\ are\ given:\\Density\ of\ aluminum=2.7\ g/cm^3\\Volume\ of\ aluminum-cube=0.9\ cm^3\\Hence,\\As\ we\ know\ that,\\Density=\frac{Mass}{Volume}\\Mass=Density*Volume\\Hence,\ here,\\Mass\ of\ the\ solid\ iron\ cube=2.7*0.9=2.43\ g\\Now,\\We\ also\ know\ that,\\Gram\ Atomic\ mass\ of\ Aluminum = 26.98 \approx 27\ g\\Hence,\\No.\ of\ particles=\frac{Mass}{GAM}*Avagadro's Constant\\Hence,\ here\\No.\ of\ Aluminum\ atoms=\frac{2.43}{27}*6.022*10^{23} \approx 0.542*10^{23}\ Aluminum\ Atoms$

8 0

3 years ago

If the sun is scaled down to 9.5 inches in diameter, the earth would be about _____ inches in diameter

vovangra [49]

Answer: 0.087 inches

Explanation:

This problem can be solved applying the Rule of three, which is a mathematical rule to find out an amount that is with another quantity given in the same relation as other two also known.

In this sense, the actual diameter of the Sun is 1,391,020 km and the actual diameter of the Earth is 12,742 km.

Now, applying the Rule of three:

Sun 1,391,020 km ------ 9.5 inches

Earth 12,742 km --------- ? inches

$? inches=\frac{(12,742 km)(9.5 inches)}{1,391,020 km}$

$? inches=0.087 inches$

Therefore:

If the sun is scaled down to 9.5 inches in diameter, the earth would be about 0.087 inches in diameter.

7 0

3 years ago