Molar mass of butane = 12g/mol*4+1g/mol*10=58g/mol
Mass of 2 moles of butane=2mol*58g/mol=116g
2c4h10(g)+13o2(g)->8co2(g)+10h2o(l)
<span>116g 8 moles</span>
<span>3.20g x</span>
116g butane/8moles CO2=3.20g butane/x
x=3.20g butane*8moles CO2/116g butane=0.2207moles CO2
T=23°C=296K
PV=nRT
V=nRT/P=0.2207moles*0.082(atm*dm³/(K/mol))*296K/(1atm)=5.36dm³
LET'S PUT IN WHAT WE KNOW!!!
Q
=
725 J
m
=
55.0 g
c
=
0.900 J/(°C⋅g)
Δ
T
=
final temperature - initial temperature
Δ
T
=
(
x
−
27.5
)
°C
We solve for
Δ
T
.
725 J
=
55.0 g
⋅
0.900 J/(°C⋅g)
(
x
−
27.5
)
°C
NOW IT'S JUST BASIC ALGREBRA
725
=
49.5
x
−
1361
2086
=
49.5
x
42.1
=
x
The final temperature is 42.1 °C.
Water could be made
to boil at 105 degrees Celsius instead of 100 degrees Celsius by taking
the sample to a higher altitude. Pressure is directly proportional to
temperature. So when you bring water into higher altitude, you are increasing
the external pressure and therefore increase the boiling point.
I think c cause if he is in a relationship that’s abusive he needs to speak up before it goes way worst.
