The equation Eºcell = 0.0592/n logK must be used to find n and also Eºcell
2 Al(s) + 3 Mg2+(aq) → 2 Al3+(aq) + 3 Mg(s) Al3+ +3e- --> Al Eº = -1.66 V Mg2+ +2e- -->Mg Eº = -2.37V
To balance the equation, 6 moles of electrons must be transferred (2 Al and 3 Mg). This will be the value of n in the equation.
To find Eºcell, you need the reduction potentials which should be given in a table, and given above. Eºcell = -1.66 - (-2.37) = 0.71 V log K = Eºcell x n/0.0592 = 0.71 x 6/0.0592 log K = 71.95 K = 10^71.95 K = 1.1x10^72
<span>Galvanized steel is preferred for outdoor uses because it is ideal to prevent rotting/corrosion
A steel will rot more quickly if it's exposed to a larger amount of oxygen and H2O , which will exist if we put it oudoor
Coating the steel with additional zinc will slow down the process</span>
I've prepared some analysis and <span>cucumbers do have many comparable properties to potatoes, tomatoes, and lemons, all of which I know do work. So I would presume that cucumbers would also work. I would recommend trying it yourself to perceive. I'd love to hear the outcomes of your experiment. ;) </span>
You have to take the 476 L and divide it by 22.4 because with Molar Volume 1 mol = 22.4L. After you divide it your answer is 21.25.
