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BARSIC [14]
4 years ago
10

What’s the unit rate of 4 and 20 8 and 40

Mathematics
2 answers:
Triss [41]4 years ago
6 0

the answer is multiplied by 5

4x5 is 20  and 8x5 is 40

Mrrafil [7]4 years ago
3 0

Answer:multiplied by 5

Step-by-step explanation:

4x5=20

8x5=40

You might be interested in
The equation of a linear graph with a y-intercept of 2/5 and a gradient -1/4 is:
sergiy2304 [10]

Answer:

C is the correct answer

7 0
3 years ago
. A box in a certain supply room contains four 40-W lightbulbs, five 60-W bulbs, and six 75-W bulbs. Suppose that three bulbs ar
yaroslaw [1]

Answer:

a) 59.34%

b) 44.82%

c) 26.37%

d) 4.19%

Step-by-step explanation:

(a)

There are in total <em>4+5+6 = 15 bulbs</em>. If we want to select 3 randomly there are  K ways of doing this, where K is the<em> combination of 15 elements taken 3 at a time </em>

K=\binom{15}{3}=\frac{15!}{3!(15-3)!}=\frac{15!}{3!12!}=\frac{15.14.13}{6}=455

As there are 9 non 75-W bulbs, by the fundamental rule of counting, there are 6*5*9 = 270 ways of selecting 3 bulbs with exactly two 75-W bulbs.

So, the probability of selecting exactly 2 bulbs of 75 W is

\frac{270}{455}=0.5934=59.34\%

(b)

The probability of selecting three 40-W bulbs is

\frac{4*3*2}{455}=0.0527=5.27\%

The probability of selecting three 60-W bulbs is

\frac{5*4*3}{455}=0.1318=13.18\%

The probability of selecting three 75-W bulbs is

\frac{6*5*4}{455}=0.2637=26.37\%

Since <em>the events are disjoint</em>, the probability of taking 3 bulbs of the same kind is the sum 0.0527+0.1318+0.2637 = 0.4482 = 44.82%

(c)

There are 6*5*4 ways of selecting one bulb of each type, so the probability of selecting 3 bulbs of each type is

\frac{6*5*4}{455}=0.2637=26.37\%

(d)

The probability that it is necessary to examine at least six bulbs until a 75-W bulb is found, <em>supposing there is no replacement</em>, is the same as the probability of taking 5 bulbs one after another without replacement and none of them is 75-W.

As there are 15 bulbs and 9 of them are not 75-W, the probability a non 75-W bulb is \frac{9}{15}=0.6

Since there are no replacement, the probability of taking a second non 75-W bulb is now \frac{8}{14}=0.5714

Following this procedure 5 times, we find the probabilities

\frac{9}{15},\frac{8}{14},\frac{7}{13},\frac{6}{12},\frac{5}{11}

which are

0.6, 0.5714, 0.5384, 0.5, 0.4545

As the events are independent, the probability of choosing 5 non 75-W bulbs is the product

0.6*0.5714*0.5384*0.5*0.4545 = 0.0419 = 4.19%

3 0
3 years ago
Josh is making 3 recipes one requires 2/3 cups of flour and otherwise 7/8 of a cup of flour in the third requires 3/4 cup of flo
kati45 [8]

Answer:

2 7/24C

Step-by-step explanation:

Start by finding the common denominator. In this case, it's 24. Next, start translation.

2/3C = 16/24C

7/8C = 21/24C

3/4C = 18/24C

Then find the sum.

16/24C + 21/24C + 18/24C = 55/24C = 2 7/24C

5 0
3 years ago
The author received a total of $195,000 for the book sales. How many hardcover books were sold? Type in numbers only.
g100num [7]

Answer:

Total 390 hardcover books were sold

Step-by-step explanation:

Complete question

The author received a total of $195,000 for the book sales. How many hardcover books were sold if the cost of one hardcover book is  $500. Type in numbers only.

Solution

Given-

Total value of sale of hard cover = $195,000

Cost of one hardcover book = $500

Number of books sold = Total value of sale of hard cover/Cost of one hardcover book

Number of books sold =   $195,000/$500

Number of books sold = 390

Total 390 hardcover books were sold.

3 0
3 years ago
Identify the linear graph.
jenyasd209 [6]

The answer is: The second one. Why?


Because, when it's a linear graph, the slope of the graph cannot change.


And that's the only graph that fits the criteria


Hope this helped! c:

5 0
3 years ago
Read 2 more answers
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