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padilas [110]
3 years ago
14

Select all of the partial products for the multiplication problem above.

Mathematics
1 answer:
allochka39001 [22]3 years ago
6 0

Answer:

all are shown and pictured

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1000+0+0+0 because its three zeroes behind the one
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Please help!!! I’ll mark you as brainliest if correct
Kryger [21]

Answer:

The Range (Statistics) The Range is the difference between the lowest and highest values. Example: In {4, 6, 9, 3, 7} the lowest value is 3, and the highest is 9. So the range is 9 − 3 = 6. It is that simple!

Step-by-step explanation:

The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.

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20. A community is having a Taste of the Town event featuring dishes from the area’s best restaurants. The cost of admission is
marin [14]

Answer:

18550 - 10x

Step-by-step explanation:

Given that :

Cost of admission in Advance = $25

Cost of admission at the door = $35

Number of people who paid in advance = x

Total number of tickets sold = 530

Total amount made from ticket sales will be :

(Number who paid in advance * cost) + (number who paid at the door * cost)

(25 * x) + (530 - x) * 35

25x + 18550 - 35x

18550 - 10x

6 0
3 years ago
Please help ! only G-J 15 points for this.
kogti [31]

Answers: G) ∠BCS = 57.5°

                H) ∠FHI = 72°

                 I) ∠ACB and also ∠DCH

                 J) ∠CHD (which can also be named ∠BHE)

<u>Step-by-step explanation:</u>

First of all, I checked your answers for A-F and they are all correct. YAY!

********************************************************************************************

G) Draw a point halfway between B and D and label it S. Then draw a ray from C passing through S.

∠ACB and ∠BCD are supplementary so

  65°    +    ∠BCD  =     180°

⇒               ∠BCD  =     115°

Since ray CS bisects ∠BCD, then ∠BCS is half of ∠BCD.

\angle BCS=\dfrac{1}{2} (\angle BCD)\\\\. \quad \quad=\dfrac{1}{2}(115^o)\\\\. \quad \quad =\large\boxed{57.5^o}

********************************************************************************************

H) The instructions state to draw a line from H to F.  This divides ∠DHI into two angles: ∠FHD and ∠FHI.  Since lines BI and EG are perpendicular, then ∠DHI = 90°.  It is given that ∠FHI is 4 times larger than ∠FHD so we can use substitution...

∠FHD + ∠FHI = ∠DHI

∠FHD + 4(∠FHD) = 90°

             5(∠FHD) = 90°

                ∠FHD  = 18°

∠FHI = 4(∠FHD)

        = 4 (18°)

        = \large\boxed{72^o}

********************************************************************************************

I) adjacent means they share a side and supplementary means they form a straight angle. There are two angles that are adjacent and supplementary to ∠ACH.  

  • ACB - they share side AC and are supplementary on BH
  • DCH - they share side CH and are supplementary on AD

********************************************************************************************

J) congruent means equal and adjacent means they share a side.

The angle that is not congruent nor adjacent to ∠GHI is its vertical angle, which is ∠CHD.  <em>Notice that ∠CHD is the same as ∠BHE.</em>

5 0
3 years ago
Suppose that there are 25 students in a class, each either a freshman, a sophomore, or a junior. How many students must be in th
Yakvenalex [24]

Answer:

at least 9 students in each cohort.

Step-by-step explanation:

Given that :

In a class, there are 25 students and each of them is either a sophomore, a freshman or a junior. We have to determine the number students in the same cohort.

Let us suppose there are equal number of students in each of the cohort.

Now let us assume that the number of the students in each cohort be 8, i.e. each as a freshman, a junior or a sophomore. Therefore, the total number in the all the cohorts will be 24 students only.

Thus, we can say that there are at least 9 freshman, at least 9 sophomore or at least 9 junior in each of the cohort.

8 0
3 years ago
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