Answer:
The answer to your question is π = 12.47 atm
Explanation:
Data
mass of Magnesium citrate = 25.5 g
volume of solution = 244 ml
temperature = 37°C
molar mass C₆H₆MgO₇ = (12 x 6) + (1 x 6) + (24 x 1) + (16 x 7) = 214 g
Osmotic pressure = π = ?
Process
1.- Calculate the moles of magnesium citrate
214 grams ----------------- 1 mol
25.5 grams --------------- x
x = (25.5 x 1)/214
x = 0.119
2.- Calculate molarity
Molarity = moles/volume
Molarity = 0.119/0.244
Molarity = 0.49
3.- Calculate osmotic pressure
π = MRT
π = (0.49)(0.0821)(37 + 273)
π = (0.49)(0.0821)(310)
π = 12.47 atm
Answer : The value of equilibrium constant (K) is, 0.004
Explanation :
First we have to calculate the concentration of 
and,
Now we have to calculate the value of equilibrium constant (K).
The given chemical reaction is:
Initial conc. 1.2 0 0
At eqm. (1.2-2x) 2x x
As we are given:
Concentration of 
at equilibrium = x = 0.1 M
The expression for equilibrium constant is:
![K_c=\frac{[SO_2]^2[O_2]}{[SO_3]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BSO_2%5D%5E2%5BO_2%5D%7D%7B%5BSO_3%5D%5E2%7D)
Now put all the given values in this expression, we get:
Thus, the value of equilibrium constant (K) is, 0.004
From electronic configuration valence electron of Nitrogen is 5, oxygen 6x2 which 12 since it involve two molecules , that of is frulorine is 7, and that No2F is 24 which is gotten form adding (5,12,7 ).All resonance structure are as follows
F
.. I ..
: O : N :O:
..
OR : F:
I
N .. : F:
/ \ or I
.. .. N
:O : :O: / / \\
/ / \\
:O : : O:
<h2>
Answer :</h2><h3><u>
QUESTION ①)</u></h3>
✔ C5H4 has a molecular molar mass of :
<em>M(C5H4) = 5 x M(C) + 4 x M(H) </em>
- M(C5H4) = 5 x 12 + 4 x 1
- M(C5H4) = 60 + 4
- M(C5H4) = 64 g/mol
✔ The molecular mass of C5H4 is therefore 64 g/mol.
<h3>This is double the molar mass of C5H4, this molecule has the formula 2C5H4.</h3>
