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horrorfan [7]
2 years ago
6

Calculate the osmotic pressure of a magnesium citrate laxative solution containing 25.5 g of magnesium citrate in 244 mL of solu

tion at 37 ∘C (approximate body temperature). Assume complete dissociation of the ionic compound.
Chemistry
1 answer:
Vera_Pavlovna [14]2 years ago
7 0

Answer:

The answer to your question is π = 12.47 atm

Explanation:

Data

mass of Magnesium citrate = 25.5 g

volume of solution = 244 ml

temperature = 37°C

molar mass C₆H₆MgO₇ = (12 x 6) + (1 x 6) + (24 x 1) + (16 x 7) = 214 g

Osmotic pressure = π = ?

Process

1.- Calculate the moles of magnesium citrate

                         214 grams ----------------- 1 mol

                          25.5 grams ---------------  x

                           x = (25.5 x 1)/214

                           x = 0.119

2.- Calculate molarity

Molarity = moles/volume

Molarity = 0.119/0.244

Molarity = 0.49

3.- Calculate osmotic pressure

π = MRT

π = (0.49)(0.0821)(37 + 273)

π = (0.49)(0.0821)(310)

π = 12.47 atm

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Answer:

A) Sample B has more calcium carbonate molecules

Explanation:

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For the 4.12 g sample

Moles of a substance is given by

n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{4.12}{100.0869}\\\Rightarrow n=0.0411\ \text{mol}

Number of molecules is given by

nN_A=0.0411\times 6.022\times 10^{23}=2.48\times 10^{22}\ \text{molecules}

For the 19.37 g sample

n=\dfrac{19.37}{100.0869}\\\Rightarrow n=0.193\ \text{mol}

Number of molecules is given by

nN_A=0.193\times 6.022\times 10^{23}=1.16\times 10^{23}\ \text{molecules}

1.16\times 10^{23}\ \text{molecules}>2.48\times 10^{22}\ \text{molecules}

So, sample B has more calcium carbonate molecules.

The ratio of the elements of carbon, oxygen, calcium atoms, ions, has to be same in both the samples otherwise the samples cannot be considered as calcium carbonate. Same is applicable for impurities. If there are impurites then the sample cannot be considered as calcium carbonate.

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Answer:

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Thus, it should be written in the undissociated form (HCN).

Hydrobromic acid is a strong acid, according to the following equation.

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Answer:

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