2a^2b^3(4a^2+3ab^2-ab)=?
<span>
is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>
Substitute this back into the original equation and you get
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) =
<span>2a^3b^3(4a-b+3b^2)
</span>
Answer:
3.1
Step-by-step explanation:
ok so
4.7j-6.8k J=5 k=3 plug in the values
4.7(5)-6.8(3)
23.5-20.4
3.1
Since you don't have b and c as a answer choice cause those are the answer
42,048,000, first solve the equation then multiply it by the number of days in a year
