Answer:
17.5 N
Explanation:
<h2>Given :</h2>
- Mass (m) = 2.5 kg
- Acceleration (a) = 7.0 m/s²
<h2>To calculate :</h2>
<h2>Calculation :</h2>
<h3>• F = ma</h3>
→ F = (2.5 × 7.0) N
→ F = 25/10 × 7 N
→ F = 5/2 × 7 N
→ F = (5 × 7)/2 N
→ F = 35/2 N
→ <u>F</u><u> </u><u>=</u><u> </u><u>1</u><u>7</u><u>.</u><u>5</u><u> </u><u>N</u><u> </u><u>towards</u><u> </u><u>left</u>
Hence, 17.5 N of net force must act on the book to make it accelerate to the left.
Answer:
If R₂=25.78 ohm, then R₁=10.58 ohm
If R₂=10.57 then R₁=25.79 ohm
Explanation:
R₁ = Resistance of first resistor
R₂ = Resistance of second resistor
V = Voltage of battery = 12 V
I = Current = 0.33 A (series)
I = Current = 1.6 A (parallel)
In series
In parallel
Solving the above quadratic equation
∴ If R₂=25.78 ohm, then R₁=10.58 ohm
If R₂=10.57 then R₁=25.79 ohm